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1 month ago

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The density of aluminum is 2.7 × 103 kg/m3 . the speed of longitudinal waves in an aluminum rod is measured to be 5.1 × 103 m/s.

what is the value of young's modulus for this aluminum?

1 answer:

ValentinkaMS [3.4K]1 month ago

5 0

<span>The speed of longitudinal waves, S, within a slender rod is calculated by the formula √(Young modulus / density), where Y is expressed in N/m^2. Thus, S = √(Young modulus / density). Squaring both sides results in S^2 = Young Modulus / density. Therefore, Young Modulus can be calculated as S^2 * density; S representing the speed of the longitudinal wave. Substituting the values into the equation gives us (5.1 *10^3)^2 * 2.7 * 10^3 = 26.01 * 10^6 * 2.7 * 10^6 = 26.01 * 2.7 * 10^(6+3) = 70.227 * 10^9</span>

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1 month ago

A 10-turn conducting loop with a radius of 3.0 cm spins at 60 revolutions per second in a magnetic field of 0.50T. The maximum e

kicyunya [3294]

Answer:

Maximum emf = 5.32 V

Explanation:

Provided data includes:

Number of turns, N = 10

Radius of loop, r = 3 cm = 0.03 m

It made 60 revolutions each second

Magnetic field, B = 0.5 T

We are tasked to determine the maximum emf produced in the loop, which is founded on Faraday's law. The induced emf can be calculated by:

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For the maximum emf, $\sin\omega t=1$

Therefore,

$\epsilon=NB\pi r^2\omega \\\\\epsilon=NB\pi r^2\times 2\pi f\\\\\epsilon=10\times 0.5\times \pi (0.03)^2\times 2\pi \times 60\\\\\epsilon=5.32\ V$

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2 months ago

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Explanation:

A substance will float if it has a lower density than the liquid it is placed in.
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2 months ago

Read 2 more answers

A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect

Softa [3030]

Answer:

$E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}$

Explanation:

Consider the following:

Length= 2L

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Distance= d

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The electric field measured at point P

$E=2K\int_{0}^{L}\dfrac{\lambda }{r^2}dx\ sin\theta$

$sin\theta =\dfrac{d}{\sqrt{d^2+x^2}}$

$r^2=d^2+x^2$

Thus,

$E=2K\lambda d\int_{0}^{L}\dfrac{dx }{(x^2+d^2)^{\frac{3}{2}}}$

Now, by applying integration to the equation above

$E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}$

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2 months ago

Below you are given data about a wave in three different substances.

inna [3103]

1) The wave's period remains constant across different media

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Clarification:

1)

The period of a wave signifies the duration it takes for one full oscillation.

The wave's period is the inverse of its frequency:

$T=\frac{1}{f}$

where

T denotes the period

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The provided table illustrates that the frequency remains consistent across the three media; hence, the period is unchanged as it solely relies on frequency. We can compute it as we know that

f = 350 Hz

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2)

The velocity of a wave can be derived from the wave equation:

$v=f \lambda$

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f indicates the frequency

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<pin the="" first="" medium="">

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In the second medium,

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As a result, we conclude that the wave's speed varies with the medium.

3)

<pwhen a="" wave="" shifts="" from="" one="" medium="" to="" another="" the="" following="" occurs:="">

- The wave's direction alters. Specifically, if the subsequent medium is of greater optical density, the wave bends towards the normal; conversely, it bends away if the second medium is of lesser optical density.

- The wave's speed is affected. The wave decelerates in media with higher optical density and accelerates in those with lower optical density.

- The wave's frequency remains unchanged.

- Ultimately, the wave's wavelength is modified. If moving into a medium of greater optical density, the wavelength decreases, while it increases in one of lower optical density.

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2 months ago