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aksik
24 days ago
6

Behold a mixture of oily/hydrophobic (yellow) and water (purplish) molecules. recall that hydrophobic regions are ones with few

or no partial charges--so there's nothing for water's hydrogen interaction donors or acceptors to 'play with'. so! how many of the water molecules are 'stuck' contacting at least part of a hydrophobic molecule in this arrangement?

Chemistry
1 answer:
Tems11 [2.4K]24 days ago
7 0

Answer:

  around 40

Explanation:

The included diagram shows 5 hydrophobic molecules, each surrounded by 9 water molecules. Therefore, there are "around 40" water molecules that are in contact with the hydrophobic molecules.

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If the 3.90 m solution from Part A boils at 103.45 ∘C, what is the actual value of the van't Hoff factor, i? The boiling point o
alisha [2718]
<span>Some solutions demonstrate colligative properties, which rely on the quantity of solute in a solvent. To find the elevation in boiling point, we use the formula:

</span><span>ΔT(boiling point)  = (Kb)mi

where Kb represents a constant, m is the solution's molality, and i is the van't Hoff factor.

From the provided information, we can easily determine i as follows:

</span>ΔT(boiling point)  = (Kb)mi
103.45 - 100  = (0.512)3.90i
i = 1.73 <-------van't Hoff factor
7 0
1 month ago
A 0.0200 M NaCl solution was formed when 38.0 grams of NaCl was dissolved in enough water. What was the total volume of the solu
Tems11 [2403]

Start by determining the number of moles, which is obtained by dividing 38 grams by the molar mass of 58.43 g/mol. This calculation yields 0.65 moles. The concentration is calculated by dividing the number of moles by the volume in liters. Using this formula, we can derive the total volume by dividing the number of moles by the concentration. Thus, 0.65 moles divided by 0.02M (mol/L) results in a total volume of 32.5 L.

4 0
1 month ago
Read 2 more answers
You are instructed to deliver about 2 mL of water from a buret with a precision of 0.01 mL. Which of the following measured volu
KiRa [2726]
The correct answer is C: 2.0 mL. This is due to the precision of the burette, which measures liquid volumes accurately with a precision of ±0.01 mL, indicating that it can reliably measure volumes around 2 mL without issue.
7 0
11 days ago
Patient added a 17-g measured dose of polyethylene glycol 3350 (MIRALAX) to 180 mL of water to use as a laxative. If the volume
Alekssandra [2719]

Answer: The apparent density of ethylene glycol 3350 is calculated as 3350 = 17g/15.6mL= 1.09g/mL

The specific gravity of the mixture is 1.01

Explanation:

Specific gravity refers to the density of a substance compared to that of a reference substance, typically water.

Specific gravity = density of substance/density of water

The density of a substance measures the mass of that substance relative to its volume.

Density = Mass/Volume

The density of water is known to be 1.00 g/mL,  

Apparent density of ethylene glycol 3350 is assessed as mass/volume

the volume of ethylene glycol = total volume of mixture - volume occupied by water

volume of ethylene glycol = 195.6 - 180 = 15.6 mL

Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

mass of water is computed as  density of water multiplied by volume of water

mass of water = 1.00g/mL * 180mL = 180 g

Total mass of solution = mass of substance plus mass of water = (17 + 180)g = 197g

Density of the mixture = total mass of the mixture divided by its volume

Density of mixture = 197 g / 195.6 mL = 1.01 g/mL

To find the specific gravity of the mixture, use the formula:

specific gravity of mixture = density of mixture divided by density of water

specific gravity of mixture = 1.01g/mL / 1.00g/mL

specific gravity of mixture = 1.01

8 0
1 month ago
In general, the presence of atoms of what element(s) makes a molecule polar
alisha [2718]
A molecule's polarity is influenced not only by specific atoms but also by its symmetry. For instance, alkanes are typically non-polar due to the absence of a net dipole moment. A dipole moment occurs because of differences in electronegativity between carbon and other elements, commonly oxygen, halogens, and nitrogen, which, due to their high electronegativity, create a net dipole moment and thus polarity.

H_3C-CH_3 exhibits symmetry and is therefore non-polar.

H_3C-O-CH_3, being asymmetrical, is polar due to its bent structure influenced by the oxygen's lone pairs.

3 0
1 month ago
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