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aliya0001
3 months ago
6

How can you tell if a sample contains baking soda and cornstarch or baking powder?

Chemistry
2 answers:
VMariaS [2.9K]3 months ago
7 0
You can test it by combining it with vinegar. The acetic acid present in vinegar reacts with sodium bicarbonate (baking soda) to produce carbon dioxide, resulting in an intense bubbling reaction that is harmless. Baking powder, however, won’t produce this effect.
KiRa [2.9K]3 months ago
4 0

Explanation:

Hi there! Let’s figure this out!

To determine if the sample contains baking soda, we can introduce vinegar.

Mixing vinegar (acetic acid) with sodium bicarbonate leads to the creation of water, carbon dioxide, and sodium acetate, resulting in visible bubbles (the carbon dioxide gas).

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Lactose, a sugar in milk, is composed of one glucose molecule joined by a glycosidic linkage to one galactose molecule. how is l
lorasvet [2795]
The classification is disaccharide.

<span>Lactose qualifies as a disaccharide since it's made up of two monosaccharides, which are simple sugars (glucose and galactose). Disaccharides constitute a subgroup of carbohydrates, and besides lactose, other common examples include sucrose and maltose.</span>

8 0
2 months ago
5 grams of NaHCO3 was added to 50 cm3 of 1.5 mol dm-3 hydrochloric acid, causing the temperature to decrease by 6.8 K. What is t
Anarel [2989]

The balanced chemical equation for the neutralization of HCl with NaHCO_{3} is:

HCl (aq) + NaHCO_{3}(aq)--> NaCl (aq) + H_{2}O(l)+CO_{2} (g)

Given weight of NaHCO_{3} = 5g

Moles of NaHCO_{3} = 5 g *\frac{1 mol}{84 g} = 0.05952 mol NaHCO_{3}

Volume of HCl solution = 50 cm^{3} * \frac{1 mL}{1cm^{3}} = 50 mL

Assuming the density of the solution is 1.0 g/mL

Mass of HCl solution = 50 g

Overall mass of the solution = 50 g + 5 g = 55 g

To find the heat of neutralization, we calculate:

Q = m C ΔT

where m equals the mass of the solution = 55 g

C represents the specific heat capacity of the solution = 4.184\frac{J}{g. ^{0}C}

ΔT signifies the temperature change = 6.8 K = (6.8 - 273) C = -266.2^{0}C

Q = 55 g * 4.184 \frac{J}{g. K}(6.8K) = 1565 J

The enthalpy of neutralization per mole of NaHCO_{3}

= \frac{1565J}{0.05952 mol} = 26294 \frac{J}{mol}*\frac{1 kJ}{1000J} =26.294kJ/mol

3 0
4 months ago
Read 2 more answers
A group of students is investigating how the addition of salt impacts the floatation of an egg in water. Four identical cups wer
VMariaS [2998]

Answer:

The dependent variable in this experiment is the egg's position above the water.

Explanation:

The dependent variable refers to the factor that is influenced by another variable.

On the other hand, the independent variable is what can be altered, affecting the dependent variable's outcome.

The controlled variable remains constant throughout the experiment.

In this setup, the amount of salt added acts as the independent variable, while the flotation level of the egg is the dependent variable, and the water volume in each cup represents the controlled variable.

7 0
2 months ago
Read 2 more answers
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