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SOVA2
2 months ago
7

A solution contains 10.0 g pentane, C5H12, 20.0 g hexane, C6H14, and 10.0 g benzene, C6H6. What is the mole fraction of hexane?

Chemistry
1 answer:
lions [2.9K]2 months ago
7 0

Answer:

b) 0.47

Explanation:

Molar mass of C5H12 = 72.15g/mol

⇒ moles of C5H12 = (10.0)*(mol/72.15)=0.1386 moles of C5H12

Molar mass of C6H14 = 86.18g/mol

⇒ moles of C6H14 = (20.0)*(mol/86.18)=0.232 moles

Molar mass of C6H6 = 78.11g/mol

⇒ moles of C6H6 = (10.0)*(mol/78.11)=0.128 moles of C6H6

Therefore, XC6H14=(0.232)/(0.1386+0.232+0.128)=0.465≅0.47

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Refer to the attached document for the solution.

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2 months ago
Find the age ttt of a sample, if the total mass of carbon in the sample is mcmcm_c, the activity of the sample is AAA, the curre
castortr0y [3046]

Answer:

Explanation:

In a desert cave, an artifact has been discovered. The anthropologists investigating this artifact want to determine its age. They note that the current activity level of the artifact is 9.25 decays/s, and the carbon mass present is 0.100 kg. To ascertain the artifact's age, they will employ specific constants:

r=1.2

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-\lambda t=In\frac{A}{A_0}

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since,

A_0=\lambda r(\frac{m_c}{m_a} )

=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )

Thus, the age of the artifact is

=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )

=-\frac{1}{1.21\times 10^{-4}} In(\frac{(9.25)(2.32\times 10^{-26}}{1.21\times 10^{-4}(\frac{1}{3.15569\times10^7} )(1.2\times 10^{-12})(0.100)}} )\\\\=6303.4 \ years

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4 0
2 months ago
Which of the following statements is true about the relationships between photon energy, wavelength, and frequency?
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Answer: The Answer is A.

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Hope this Helps!

8 0
2 months ago
An unknown liquid has a mass of 4.25 × 108 mg and a volume of 0.250 m3. what is the density of the liquid in units of g/ml?
VMariaS [2998]
Density is calculated as mass divided by volume.
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8 0
2 months ago
Read 2 more answers
An impure sample of zinc (zn) is treated with an excess of sulfuric acid (h 2 so 4) to form zinc sulfate (znso4) and molecular h
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Zn(s) + H2SO4(aq) --------> ZnSO4(aq) + H2 (g) 

<span>b) Initially, we determine the quantity of zinc that has reacted based on the produced H2.</span>

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<span>c) In part (b), it is assumed that the impurities in the sample do not react with sulfuric acid to emit hydrogen. Thus, the hydrogen solely arises from the reaction of Zn with sulfuric acid.</span>

7 0
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