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love history
2 months ago
9

An article in Fire Technology, 2014 (50.3) studied the effectiveness of sprinklers in fire control by the number of sprinklers t

hat activate correctly. The researchers estimate the probability of a sprinkler to activate correctly to be 0.7. Suppose that you are an inspector hired to write a safety report for a large ballroom with 10 sprinklers. Assume the sprinklers activate correctly or not independently. (a) What is the probability that all of the sprinklers will operate correctly in a fire
Mathematics
1 answer:
Zina [12.3K]2 months ago
5 0
The likelihood of all sprinklers functioning properly in a fire stands at 0.0282. This was determined via the Binomial probability distribution since the activation of sprinklers occurs independently. There are two potential outcomes: they either function correctly or they do not. The binomial distribution is used to calculate the probabilities over multiple trials. The resulting equation b(x; n, P) = P(X=x) considers the number of successes, probability of success in a singular attempt, and the number of trials involved. The computations conclude with the probability being reflected as 0.0282.
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Jackie runs and dances for 75 minutes every day.
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A. x + y = 75 B. She dedicates 25 minutes to running and 50 minutes to dancing daily. C. Yes, that's correct.
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In the diagram, DG = 15, GF = 5, EH = 12, and DE = 8. To prove that △DFE ~ △GFH by the SSS similarity theorem using the informat
lawyer [12517]

Answer: C) HF measures 4 units and GH is 2 units.

Step-by-step explanation:

The SSS similarity theorem asserts that triangles are similar if the lengths of their corresponding sides are in proportion.

For triangles ΔDFE and ΔGFH:

DG equals 15, GF is 5, EH equals 12, and DE is 8.

To demonstrate the similarity of ΔDFE and ΔGFH according to the SSS similarity theorem, we require:

\frac{DF}{GF}=\frac{FE}{FH}=\frac{DE}{GH}\\\\\Rightarrow\frac{DG+GF}{GF}=\frac{FH+EH}{FH}=\frac{DE}{GH}\\\\\Rightarrow\frac{5+15}{5}=\frac{12+HF}{FH}=\frac{8}{GH}\\\\\Rightarrow\frac{20}{5}=\frac{12+HF}{FH}\ and\ \frac{20}{5}=\frac{8}{GH}\\\\\Rightarrrow4HF=12+HF\ and\ GH=\frac{8}{4}\\\\\Rightarrow3HF=12\ and\ GH=2\\\\\Rightarrow HF=4\ and\ GH=2

Thus, to confirm that △DFE is similar to △GFH utilizing the SSS similarity theorem and the data from the diagram, it is essential to establish that HF measures 4 units and GH measures 2 units.

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2 months ago
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At what rate would you need to invest $12000 and make $2880 after 8 years?
PIT_PIT [12445]

Answer:

3\%

Step-by-step explanation:

We start with the fact that

The formula for simple interest is represented by

I=P(rt)

where:

I denotes the Final Interest Value

P indicates the Principal amount to be invested

r specifies the interest rate

t refers to the Number of Time Periods

For this scenario, we have

t=8\ years\\ P=\$12,000\\I=\$2,880\\r=?

We can substitute these values into the formula mentioned above

2,880=12,000(8r)

Next, we solve for t

2,880=96,000(r)

r=2,880/96,000

r=0.03

Convert to a percentage format

0.03*100=3\%

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2 months ago
In triangle JKL, sin(b°) = three fifths and cos(b°) = four fifths. If triangle JKL is dilated by a scale factor of 2, what is ta
Inessa [12570]

Answer:

Tan(b°) = 3/4, which is equivalent to three fourths (C).

Step-by-step explanation:

Triangle JKL is a right triangle with angle K being the right angle and angle L equal to b°.

We will employ SOHCAHTOA principles from trigonometry to calculate the sides' values.

For triangle ∆JKL:

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4.

From the earlier information, we have the values for each side of triangle ∆JKL.

Please refer to the attached diagram for the triangle (1).

Triangle ∆JKL is scaled with a factor of 2.

This implies multiplying each side of ∆JKL by 2, resulting in:

Opposite side = 2(3) = 6

Adjacent side = 2(4) = 8

Hypotenuse = 2(5) = 10.

To find tan(b°) for the new triangle, we use the tangent ratio:

Tan(b°) = opposite/adjacent.

Tan(b°) = 6/8.

Tan(b°) = 3/4.

Find the diagram for the new triangle included (2).

Diagram 3 provides a depiction of both triangles.

As shown, the angle remains unchanged when a triangle is scaled by a factor.

Thus, we conclude that tan(b°) = three fourths (C).

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