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Ymorist
1 month ago
14

Which occurrence would contradict the big bang theory?

Physics
2 answers:
inna [3.1K]1 month ago
6 0

Solution:

The assertion that is at odds with the big bang theory isAs time progresses, remote galaxies are actually drifting closer to Earth.

Clarification:

In 1927, Georges Lemaître, a Belgian Catholic priest, introduced an expanding universe model to clarify the observed redshifts of spiral nebulae, and formulated the Hubble law. This set the groundwork for the Big Bang Theory, which posits that the universe is expanding. There is no mention of a contraction of celestial objects towards the Earth.

Maru [3.3K]1 month ago
3 0
The big bang theory posits that all matter composing the universe originated from an extremely small and dense point. Subsequently, this point exploded, leading to the formation of the universe as we recognize it. A fundamental aspect supporting the idea that the universe emerged from the big bang explosion was established by Hubble, who demonstrated that the universe is expanding; thus, in general, galaxies are receding from earth. The scenario that contradicts the big bang theory is: "Over time, distant galaxies move progressively closer to Earth."
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A car traveling at 70 mph70 mph down the interstate collides with a bug trying to cross the highway. Which of the following stat
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The force exerted by the car on the bug is identical to the force the bug applies back on the car.
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Justine is ice-skating at the Lloyd Center what is her final velocity if she accelerates at a rate of 2.0 meters per second for
Ostrovityanka [3204]

2*3.5 = 7m/s

You need to multiply the acceleration by the time (which must both be in seconds; if not, convert them to the same units).

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1 month ago
One consequence of Einstein's theory of special relativity is that mass is a form of energy. This mass-energy relationship is pe
ValentinkaMS [3465]

Answer:

The energy unit is expressed as kg-m/s or Joules.

Explanation:

The relationship between mass and energy in physics is represented by:

E=mc^2

Where

m denotes the mass of the object

c signifies the speed of light

In the SI system, mass is measured in kilograms and the speed of light in m/s. Therefore, energy is defined in kg-m/s, which is equal to Joules.

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6 0
2 months ago
Read 2 more answers
The amount of electric energy consumed by a 60.0-watt lightbulb for 1.00 minute could lift a
Sav [3153]

Answer:

Explanation:

For a 60W light bulb used for 1 minute:

P = 60 W

t = 1 minute = 60 seconds

This energy is capable of lifting an object weighing 10N.

W = 10N

This indicates conversion of electrical energy into potential energy.

Let's calculate the electrical energy:

Power describes the rate of work done.

Power = Work / time

Thus, work = power × time

Work = 60 × 60

Work = 3600 J

Potential energy calculation:

P.E = mgh

Where the weight is given by:

W = mg

Therefore, P.E = W·h

P.E = 10·h

Thus, we equate:

Potential energy = Electrical energy

P.E = Work

10·h = 3600

Dividing both sides by 10 gives:

h = 3600 / 10

h = 360m

The object can be lifted to a height of 360m.

6 0
2 months ago
10. How far does a transverse pulse travel in 1.23 ms on a string with a density of 5.47 × 10−3 kg/m under tension of 47.8 ?????
serg [3582]

Answer: Tension = 47.8N, Δx = 11.5×10^{-6} m.

              Tension = 95.6N, Δx = 15.4×10^{-5} m

Explanation: The speed of a wave on a string under tension can be determined using the following:

|v| = \sqrt{\frac{F_{T}}{\mu} }

F_{T} denotes tension (N)

μ refers to linear density (kg/m)

Calculating the velocity:

|v| = \sqrt{\frac{47.8}{5.47.10^{-3}} }

|v| = \sqrt{0.00874 }

|v| = 0.0935 m/s

Distance a pulse traveled in 1.23ms:

\Delta x = |v|.t

\Delta x = 9.35.10^{-2}*1.23.10^{-3}

Δx = 11.5×10^{-6}

With a tension of 47.8N, the distance a pulse will cover is Δx = 11.5×10^{-6}  m.

When tension is doubled:

|v| = \sqrt{\frac{2*47.8}{5.47.10^{-3}} }

|v| = \sqrt{2.0.00874 }

|v| = \sqrt{0.01568}

|v| = 0.1252 m/s

Distance in the same time:

\Delta x = |v|.t

\Delta x = 12.52.10^{-2}*1.23.10^{-3}

\Delta x = 15.4×10^{-5}

With the increased tension, it moves \Delta x = 15.4×10^{-5} m

4 0
2 months ago
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