Answer:
Dₓ = -155 sin 23° i + 0 j
Explanation:
The accompanying diagram illustrates the vector.
According to the diagram,
The vector D has an x-component (or horizontal component) expressed as -D sinθ i. Specifically,
Dₓ = -D sin θ i [The negative sign indicates that D is directed along the negative x-axis]
Where;
D = magnitude of D = 155m
θ = angle of D = 23°
Consequently;
Dₓ = -155 sin 23° i
Since Dₓ signifies the x component, its unit vector, j component holds a value of 0.
<pthus d="" can="" be="" formulated="" in="" terms="" of="" and="" the="" unit="" vectors="" i="" j="" as="" follows="">
Dₓ = -155 sin 23° i + 0 j
</pthus>
Kepler's third law, referred to as the law of harmonies, is used to calculate the orbital period and radius of a planet based on the dimensions and periods of another planet. This relationship is directly proportional to the square of the period and inversely proportional to the cube of the distance. Therefore, when the distance is tripled ((3D)^3), the period should increase to the square root of 27 times 5.20 times the initial period,
Answer:
20.353125 V
Explanation:
m = Mass of proton = 
q = Charge of proton = 
= Velocity of proton at point A = 50 km/s
= Velocity of proton at point B = 80 km/s
The relationship derived from energy conservation is as follows:
The determined potential difference is 20.353125 V
The magnetic field is calculated to be -6.137 × T. Explanation: Given the radio wave wavelength of λ = 0.3 m and an intensity of I = 45 W/m² at times t = 0 and t = 1.5 ns, we determine Bz at the origin. We use the intensity formula relating to the electric field, which incorporates the known intensity of 45, the speed of light c = 3 × m/s², and ∈o as 8.85 × C²/N.m², leading us to E = 184.15. Consequently, applying the equations, we find B = -6.137 × T at the z-axis.
Since it's classified as a transverse wave, the particle on the string moves horizontally as the wave progresses, without actual forward or backward travel. Consequently, the red dot shifts 'A' to the left, returns 'A' to the center, moves 'A' to the right, and goes back 'A' to the center once again. Thus, the red dot collectively travels a distance totaling 4A.
