All categories

12 days ago

What is the torque τa about axis a due to the force f⃗ ? express the torque about axis a at cartesian coordinates (0,0)?

Physics

1 answer:

Yuliya22 [2.4K]12 days ago

5 0

Response:

$\tau_a = F a sin \theta$

Explanation:

Torque is defined as:

$\tau = F d sin \theta$

where

F is the force's magnitude,

d represents the distance from where the force is applied to the center of rotation,

$\theta$ and is the angle between the force's direction and d.

In this question, we have:

$F$ , the force

$a$ , the distance of applying the force from the center (0,0)

$\theta$ , and the angle between the force's direction and a.

Thus, the torque is

$\tau_a = F a sin \theta$

You might be interested in

Mosses don't spread by dispersing seeds; they disperse tiny spores. The spores are so small that they will stay aloft and move w

Keith_Richards [2268]

Solution:

$Em_{f}$ / Em₀ = 0.30

Explanation:

In this problem, we apply the connection between mechanical energy, kinetic energy, and gravitational potential energy.

K = ½ m v²

U = mgh

We assess the mechanical energy at two positions:

Initial. Lower

Em₀ = K = ½ m v²

At its highest point

$Em_{f}$ = U = mg and

Now let's compute

Em₀ = ½ m 3.6²

Em₀ = m 6.48

$Em_{f}$ = m 9.8 × 0.2

$Em_{f}$ = m 1.96

Thus the energy lost is given by:

$Em_{f}$ / Em₀ = m 1.96 / m 6.48

$Em_{f}$ / Em₀ = 0.30

This means that 30% of the sun's energy is transformed into potential energy.

There are various conversion possibilities.

This energy changes into thermal energy affecting the spores and air, since it cannot be regained.

8 0

14 days ago

What is the gauge pressure of the water right at the point p, where the needle meets the wider chamber of the syringe? neglect t

Yuliya22 [2446]

Details that are not provided: the problem figure is included.

We can address the exercise by applying Poiseuille's law. This law indicates that for a fluid flowing in a laminar manner within a confined pipe,

$\Delta P = \frac{8 \mu L Q}{\pi r^4}$

where:

$\Delta P$ represents the pressure difference across the two ends

$\mu$ denotes the viscosity of the fluid

L signifies the length of the pipe

$Q=Av$ indicates the volumetric flow rate, where $A=\pi r^2$ is the cross-sectional area of the tube and $v$ refers to the fluid's velocity

r stands for the pipe's radius.

This law can be utilized for the needle, allowing us to compute the pressure difference between point P and the needle's end. In this scenario, we have:

$\mu=0.001 Pa/s$ is the dynamic viscosity of water at $20^{\circ}$

L=4.0 cm=0.04 m

$Q=Av=\pi r^2 v= \pi (1 \cdot 10^{-3}m)^2 \cdot 10 m/s =3.14 \cdot 10^{-5} m^3/s$

and r=1 mm=0.001 m

Substituting these values into the formula yields:

$\Delta P = 3200 Pa$

This pressure difference specifies the value between point P and the needle's termination. As the end of the needle is under atmospheric pressure, the gauge pressure at point P, relative to atmospheric pressure, is exactly 3200 Pa.

8 0

1 month ago

Considering the activity series given for nonmetals, what is the result of the below reaction? Use the activity series provided.

ValentinkaMS [2433]

Response: The result would be no reaction.

Clarification:

7 0

9 days ago

Read 2 more answers

A careful photographic survey of Jupiter’s moon Io by the spacecraft Voyager 1 showed active volcanoes spewing liquid sulfur to

Sav [2230]

Answer:

529.15 m/s

Explanation:

h = Highest point = 70000 m

g = Gravitational acceleration = 2 m/s²

m = Sulfur's mass

Since both potential and kinetic energies are conserved

$mgh=\dfrac{1}{2}mv^2\\\Rightarrow h=\dfrac{v^2}{2g}\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 2\times 70000}\\\Rightarrow v=529.15\ m/s$

The velocity at which the liquid sulfur exited the volcano is 529.15 m/s

7 0

24 days ago

A book that weighs 0.35 kilograms is kept on a shelf that’s 2.0 meters above the ground. A picture frame that weighs 0.5 kilogra

Softa [2035]

Upon calculating, I'm nearly certain that the answer is "...to a height of 1.4 meters." Happy to assist!:)

4 0

9 days ago

Read 2 more answers