A bowling pin is thrown vertically upward such that it rotates as it moves through the air, as shown in the figure. Initially, t

answer:

1950 g This is the result of lead being spread out in kilograms

Answer:

The excess charge is

Explanation:

According to the question, we are informed that

The diameter is

The potential of the surface is

The radius of the sphere is

by plugging in given values

The potential at the surface is mathematically expressed as

Where k is Coulomb's constant with a value

Based on the question stating there are no other charges, Q represents the excess charge

Therefore

inserting the numerical values

For motion in a circle.

Centripetal acceleration is calculated as mv²/r = mω²r

where v represents linear velocity, r equals radius which is diameter/2 equating to 1/2 or 0.5m

. Here, m is the mass of the object, which is 175g or 0.175kg.

The angular speed, ω, is derived from Angle covered / time

                         = 2 revolutions per 1 second

                         = 2 * 2π  radians for each second

                         = 4π  radians per second

Thus, Centripetal Acceleration = mω²r = 0.175*(4π)² * 0.5. Utilize a calculator

                                                         ≈13.817  m/s²

. The acceleration's magnitude is approximately 13.817  m/s² and it is oriented towards the center of the circular path.

The tension in the string equates to m*a

                                   = 0.175*13.817

                                   = 2.418 N

Hello! Thanks for sharing your query here.

To determine the change in potential energy, you would utilize the formula:

delta PE = mg*delta h
delta PE = 0.5*9.81*(2-1.8)
delta PE = 0.98 J

The kinetic energy is derived from the potential energy.