Answer:
Approximately, Hannah has completed 7 laps.
Solution:
Based on the provided details:
The complete distance to run, D = 5000 m
The distance for one lap, x = 400 m
Kara's time taken, 
Hannah's time taken, 
The speed for both Kara and Hannah can be determined as follows:


The time taken for each lap is represented by:



t = 500 s
Thus, the distance that Hannah covers in 't' seconds is given by:


The number of laps completed by Hannah when she overtakes Kara:

≈ 7 laps
The maximum speed around this curve before a toolbox made of steel slips off the truck bed is: 14.832 m/s
Further explanation
The centripetal force acts on objects in circular motion, directed towards the circle's center.

F = centripetal force, N
m = mass, Kg
v = linear velocity, m / s
r = radius, m
The velocity directed toward the center of the circle is referred to as linear velocity.
It can be represented as:

r = radius of the circle
f = rotations per second (RPS)
Pickup trucks negotiating a curve are influenced by centripetal forces. To prevent the steel toolbox from slipping off the bed of the truck, the centripetal force acting on it must equal its weight. Should the centripetal force surpass the toolbox's weight, it will fall off.
centripetal force = weight

Thus, the maximum velocity to keep the toolbox secure is:

For a curve with a radius of 22 m, it follows that:

Learn more
The average velocity
Resultant velocity
Velocity position
The complete question is;
A ski jumper descends a ramp and exits the ski track at a horizontal speed of 24 m/s. The slope at the landing site angles downwards at θ = 59◦. The acceleration due to gravity is 9.8 m/s².
What is the value of the relative angle φ at which the ski jumper makes contact with the slope? Provide the answer in degrees.
Answer:
14.08°
Explanation:
The time taken can be calculated using the formula;
t = (2V_x•tan θ)/g
t = (2 × 24 × tan 59)/9.8
t = 8.152 s
Next, the slope of the trajectory at the impact point is determined by;
tan α = V_y/V_x
Given V_x = 24 m/s
We will find V_y using;
v = gt
Therefore;
V_y = gt
V_y = 9.8 × (8.152) = 78.89 m/s
Thus;
tan α = 78.89/24
tan α = 3.2871
α = tan^(-1) 3.2871
α = 73.08°
Consequently;
Relative angle φ = α - θ = 73.08 - 59 = 14.08°