Answer:
θ = 61.3°
Alicia must swim at an angle of 61.3°
Explanation:
Parameters given include:
Width of the river = 100 m
Alicia's speed in still water = 2.5 m/s
Speed of river's current = 1.2 m/s
The angle she needs to swim can be determined by combining the velocities, taking into account the current's influence.
Her swimming speed aimed against the current must offset the current's velocity;
2.5cosθ - 1.2 = 0
2.5cosθ = 1.2
cosθ = 1.2/2.5
θ = cosinverse(1.2/2.5)
θ = 61.3°
Answer:
a) 
b) 
c) 
Explanation:
According to the problem, the distance from the building where the ball hits is 16m, and its final elevation exceeds the initial height by 8m.
With this information, we can compute the ball’s starting speed.
a) Let's first assess the horizontal trajectory.


(1)
This gives us our initial equation.
Next, we need to examine the vertical trajectory.


Utilizing
in our first equation (1)


Now let’s solve for t.

The ball takes two seconds to reach the adjacent building, allowing us to compute its initial speed.

b) To determine the velocity magnitude just before impact, we must calculate both x and y components.


The computed velocity magnitude is:

c) The ball's angle is:

Answer:
consult a teacher
Explanation:
go to your school
locate the teacher
request assistance from him/her
complete the question and you're done:)
Answer:
H = 109.14 cm
Explanation:
Given,
Assume that the total energy equals 1 unit.
Energy remaining after the first collision = 0.78 x 1 unit
Balance after the first impact = 0.78 units
Remaining energy after the second impact = 0.78 ^2 units
Balance after the second impact = 0.6084 units
Remaining energy after the third impact = 0.78 ^3 units
Balance after the third impact = 0.475 units
The height reached after the third collision is equivalent to the remaining energy.
Let H denote the height achieved after three bounces.
0.475 (m g h) = m g H
H = 0.475 x h
H = 0.475 x 2.3 m
H = 1.0914 m
H = 109.14 cm
Answer
Data provided:
mass of the block = 200 g = 0.2 Kg
Velocity at A = 0 m/s
Velocity at B = 8 m/s
distance of slide = 10 m
height of the block = 4 m
calculation for the block's potential energy
P = m g h
P = 0.2 x 9.8 x 4
P = 7.84 J
kinetic energy calculated as



Work done = P - KE
work = 7.84 - 6.14
work = 1.7 J
b) using the formula v² = u² + 2 a s
0 = 8² - 2 x a x 10
a = 3.2 m/s²
ma - μ mg = 0


