A block moves at 5 m/s in the positive x direction and hits an identical block, initially at rest. A small amount of gunpowder h

Answer:

b) TA = TB = TC

Explanation:

• When the blocks are brought into contact and isolated from the environment, they will exchange heat until they achieve thermal equilibrium.
• During this exchange, the hotter body will lose heat, which will be gained by the cooler body.
• The equilibrium state will be established once this equation is satisfied:

• Substituting the initial temperatures T₀A = 300º C and T₀B = 400ºC, while simplifying for equal block masses mA = mB, enables us to solve for the final temperature, Tfin:

• At equilibrium, when both blocks combine, they will yield a uniform final temperature of 350ºC.
• When block C, also at this temperature, makes contact, all three blocks will simultaneously reflect this final temperature of 350 ºC.
• Therefore, option b) is correct.

Answer:

b. 9.5°C

Explanation:

= Ice mass = 50 g

= Initial temperature of water and aluminum = 30°C

= Latent heat of fusion =

= Water mass = 200 g

= Water's specific heat = 4186 J/kg⋅°C

= Aluminum mass = 80 g

= Aluminum's specific heat = 900 J/kg⋅°C

The equation governing heat exchange in the system is presented by

The final equilibrium temperature calculates to 9.50022°C

Set the initial location of kitten A on the left side of the field (designated as point A) at the origin, running east which is the positive direction. Kitten B starts at position , while kitten A’s beginning spot is .

Kitten A moves with a velocity of , and kitten B with . Their positions over time are described by

The collision occurs when the positions are the same, i.e. when . Solving this gives

Which results in approximately 6.8 seconds, considering significant figures.

Answer:

The peak mechanical energy transformed into internal energy throughout the descent is 26.7 joules.

Explanation:

Potential Energy (PE) is calculated as the weight of the baseball multiplied by the height, which gives us 1.47N × 10m = 14.7Nm or 14.7 joules.

The kinetic energy (KE) is recorded as 12 joules.

The maximum mechanical energy that converts to internal energy during the fall can be expressed as PE + KE = 14.7 joules + 12 joules = 26.7 joules.

Answer:

The required force to stretch the steel guitar string by 0.500 mm is 10.1 N

Explanation:

The steel guitar string diameter is 0.300 mm and its length measures 70.0 cm. To calculate the force required for the specified elongation using Young's modulus, one would apply the relevant formulas, yielding 10.1 N.