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Svetradugi
1 month ago
14

How much water must be added to 36.0 g of srcl2 to produce a solution that is 35.0 wt% srcl2? how much water must be added to 36

.0 of to produce a solution that is 35.0 wt% ? 48.6 g 66.9 g 103 g 97.2 g?
Chemistry
1 answer:
Tems11 [2.7K]1 month ago
8 0
To address this issue, we can apply the following equation:

w = (mass of solute) / (mass of solution)

w - percentage

It is important to note that the mass of the solution is the sum of the mass of the solute and the mass of the water.

<span>w = mass CaCl2/(mass of water + mass of CaCl2)
</span>
mass of water = x

0.35 = 36 / (x + 36)

0.35 × (x + 36) = 36

0.35x + 12.6 = 36

0.35x = 23.4

x = 66.86 g of water is required




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