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Answer:

The integer value of x in the hydrate is 10.

Explanation:

Molar concentration of the solution = 0.0366 M

Volume of the solution = 5.00 L

Moles of hydrated sodium carbonate = n

Weight of hydrated sodium carbonate = n = 52.2 g

Molar mass of hydrated sodium carbonate = 106 g/mol + x * 18 g/mol

By solving for x, we arrive at:

x = 9.95, approximating to 10

The integer x in the hydrate equals 10.

Answer: The number of sulfur dioxide molecules present is 1.27·10²³.
Calculating: m(SO₂) equals 13.5 g.
Using the formula n(SO₂) = m(SO₂) ÷ M(SO₂).
This gives n(SO₂) = 13.5 g ÷ 64 g/mol.
Resulting in n(SO₂) = 0.21 mol.
Subsequently, N(SO₂) = n(SO₂) ·Na.
Therefore, N(SO₂) = 0.21 mol · 6.022·10²³ 1/mol.
Ultimately, N(SO₂) equals 1.27·10²³.
Where n represents amount of substance.
M refers to molar mass.
Na is Avogadro's number.

The quantity of fluorine in moles is calculated as 71/19 = 3.74
We also know that at standard temperature and pressure (273 K and 101.3 kPa), one mole of gas occupies 22.4 liters
So, the volume for 3.74 moles at S.T.P is: 3.74 x 22.4
This results in a volume of 83.776 L, which is equivalent to 83,776 mL

Next, applying Boyle's law, which states that for a fixed amount of gas,
PV = constant

We set up the equation P x 6843 = 101.3 x 83776
Solving for P gives us 1,240 kPa

It must be a physical change unless a chemical substance interacts with the metal surface, resulting in a chemical change.

Answer: The apparent density of ethylene glycol 3350 is calculated as 3350 = 17g/15.6mL= 1.09g/mL

The specific gravity of the mixture is 1.01

Explanation:

Specific gravity refers to the density of a substance compared to that of a reference substance, typically water.

Specific gravity = density of substance/density of water

The density of a substance measures the mass of that substance relative to its volume.

Density = Mass/Volume

The density of water is known to be 1.00 g/mL,  

Apparent density of ethylene glycol 3350 is assessed as mass/volume

the volume of ethylene glycol = total volume of mixture - volume occupied by water

volume of ethylene glycol = 195.6 - 180 = 15.6 mL

Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

mass of water is computed as  density of water multiplied by volume of water

mass of water = 1.00g/mL * 180mL = 180 g

Total mass of solution = mass of substance plus mass of water = (17 + 180)g = 197g

Density of the mixture = total mass of the mixture divided by its volume

Density of mixture = 197 g / 195.6 mL = 1.01 g/mL

To find the specific gravity of the mixture, use the formula:

specific gravity of mixture = density of mixture divided by density of water

specific gravity of mixture = 1.01g/mL / 1.00g/mL

specific gravity of mixture = 1.01