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Volgvan
1 month ago
8

What mass of boron sulfide must be processed with 2.1 x 10 4g of carbon to yield 3.11 x 10 4 g of boron and 1.47 x 10 5 g of car

bon sulfide ?
Chemistry
1 answer:
alisha [2.9K]1 month ago
4 0

The reaction involving boron sulfide and carbon is expressed as:

2B2S3 + 3C → 4B + 3CS2

According to the conservation of mass principle, the sum of the masses of the reactants must equal the total mass of the products in any chemical reaction.

The relevant data provided includes:

Mass of C = 2.1 * 10^ 4 g

Mass of B = 3.11*10^4 g

Mass of CS2 = 1.47*10^5

Mass of B2S3 =?

Now, applying the conservation of mass principle:

Mass of B2S3 + mass of C = mass of B + mass of CS2

Mass of B2S3 + 2.1 * 10^ 4 = 3.11*10^4 + 1.47*10^5

This gives us the mass of B2S3 = 15.7 * 10^4 g


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A laboratory utilizes a mixture of 10% dimethyl sulfoxide (DMSO) in the freezing and long-term storage of embryonic stem cells.
Alekssandra [3086]

Answer:

The right answer is "1.0100".

Explanation:

Assuming the total volume of the mixture is 100 ml.

Thus,

The volume of DMSO will be 10 mL and the volume of water will be 90 mL.

For DMSO:

= 10\times 1.1004

= 11.004 \ g

The total mass of the mixture will be:

= 90+11.004

= 101.004 \ g

Calculating the density of the mixture:

= \frac{Mass}{Volume}

= \frac{101.004}{100}

= 1.01004 \ g/mL

Thus,

The specific gravity of the mixture is:

= \frac{Density \ of \ mixture}{Density \ of \ water}

= \frac{1.01004}{1}

= 1.0100

3 0
2 months ago
A certain metal alloy is composed of 10% tin, 16% antimony, and 74% lead. If you were to have 500 g of the alloy, how many grams
Anarel [2989]
80 g. Explanation: In the metal alloy, the weight percent of antimony can be determined using the formula wt% = (mass of compound/mass of alloy)×100. Since we have 16% = (grams of antimony / grams of alloy)×100, simplifying gives us 0.16 = grams of antimony / grams of alloy, and therefore if the alloy is 500 g, it leads us to the conclusion that the weight of antimony is 80 g.
3 0
1 month ago
An infant acetaminophen suspension contains 80 mg/0.80 mL suspension. The recommended dose is 15 mg/kg body weight.
KiRa [2933]

Response:

0.8853 mL

Clarification:

Initially, we convert 13 lb to kg, remembering that 1 lb = 0.454 kg:

  • 13 lb * \frac{0.454kg}{1lb} = 5.902 kg

Next, we determine the required mg of acetaminophen to administer, applying the recommended dosage and infant's weight:

  • 15 mg/kg * 5.902 kg = 88.53 mg

Finally, we compute the necessary mL of suspension, utilizing its concentration:

  • 88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL
8 0
2 months ago
A 25.0-g sample of ice at -6.5oC is removed from the freezer and allowed to warm until it melts. Given the data below, select al
KiRa [2933]

Answer:

B, D

Explanation:

We need to recognize that the ice will rise in temperature from -6.5 ºC to 0 ºC for it to change into water.

Let's define q₁ as the heat needed to warm the ice to 0ºC, and q₂ as the heat for the transition from solid to liquid.

The calculation for q₁ is as follows:

q₁ = s x m x ΔT, where s represents the specific heat of ice (2.09 J/gºC), m is the mass, and ΔT is the temperature difference.

For q₂, the enthalpy of fusion is computed as:

q₂ = C x ΔT

with C indicating the specific heat for the phase transition, denoted as AH in kJ/mol.

All necessary data for computing q₁, q₂, and the total heat change (q₁ + q₂) is provided.

q₁ = 25.0 g x (2.09 J/gºC) x (0 - (-6.5 ºC))

q₁ = 339.6 J = 0.339 kJ

q₂ = (25 g/18 g/mol) x 6.02 kJ/mol = 1.39 x 6.02 kJ = 8.36 kJ

Combining these values gives us qtotal = 0.339 kJ + 8.36 kJ = 8.70 kJ.

Now we can answer the question:

(a) False, AH refers to the heat capacity during melting.

(b) True, as we concluded earlier.

(c) False, there’s only one phase transition from solid (ice) to liquid.

(d) True based on our calculations above.

(e) False, according to our findings.

7 0
2 months ago
Compare and contrast these isotopes: uranium -239, uranium -238, and uranium -235
eduard [2782]
Each isotope contains an identical number of protons and electrons, but they vary in neutron count, making them isotopes.
4 0
1 month ago
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