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tino4ka555
1 month ago
5

The manager of the BiLo Supermarket in Mt. Pleasant, Rhode Island, gathered the following information on the number of times a c

ustomer visits the store during a month. The responses of 51 customers were: 5 3 3 1 4 4 5 6 4 2 6 6 6 7 1 1 14 1 2 4 4 4 5 6 3 5 3 4 5 6 8 4 7 6 5 9 11 3 12 4 7 6 5 15 1 1 10 8 9 2 12 a. Starting with 0 as the lower limit of the first class and using a class interval of 3, organize the data into a frequency distribution. b. Where do the data tend to cluster? 12 up to 15 15 up to 18 3 up to 6 6 up to 9 0 up to 3 9 up to 12 c. Convert the distribution to a relative frequency distribution. (Round your answers to 2 decimal places.)

Mathematics
1 answer:
AnnZ [12.3K]1 month ago
7 0

Answer: please see the explanation

Step-by-step breakdown:

Provided data:

5 3 3 1 4 4 5 6 4 2 6 6 6 7 1 1 14 1 2 4 4 4 5 6 3 5 3 4 5 6 8 4 7 6 5 9 11 3 12 4 7 6 5 15 1 1 10 8 9 2 12

The frequency and relative frequency table is available in the attachment below.

b. What is the clustering of the data?

3 to 6

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The present age of Alex is ‘y’ years. Answer the following
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Answer:

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Why might the triangulation method not always produce an exact point (other than any measurement errors)
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The triangulation technique may not always yield a precise result (aside from any errors in measurement) for the following reasons:

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The idle time for taxi drivers in a day are normally distributed with an unknown population mean and standard deviation. If a ra
Svet_ta [12734]

Answer:

172-2.51\frac{16}{\sqrt{23}}=163.626    

172+2.51\frac{16}{\sqrt{23}}=180.374

Hence, in this case, the 98% confidence interval would be (163.626;180.374)    

Step-by-step breakdown:

Previous concepts

A confidence interval represents a range that is likely to encompass a population value within a specific confidence level, typically expressed as a percentage whereby a population mean falls between an upper and lower limit.

The margin of errorindicates the span of values surrounding the sample statistic in a confidence interval.

A normal distributionillustrates a probability distribution that is symmetrical around the mean, signifying that values near the mean occur more frequently than those farther away from it.

\bar X=172 denote the sample mean

\mu population mean (the variable of interest)

s=16 signifies the sample standard deviation

n=23 represents the sample size  

The solution to the query

The equation for the confidence interval of the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

To determine the critical value t_{\alpha/2}, we first need to calculate the degrees of freedom, which is expressed as:

df=n-1=23-1=22

Since the confidence level is 0.98 or 98%, we find the value of \alpha=0.02 and \alpha/2 =0.01 using tools like Excel or a calculator, where the Excel command would be: "=-T.INV(0.01,22)". This yields t_{\alpha/2}=2.51

Having all components ready, we can substitute into formula (1):

172-2.51\frac{16}{\sqrt{23}}=163.626    

172+2.51\frac{16}{\sqrt{23}}=180.374

Thus, for this case, the 98% confidence interval will be (163.626;180.374)    

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