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jonny
3 months ago
11

Two astronauts, A and B, both with mass of 60Kg, are moving along a straight line in the same direction in a weightless spaceshi

p. Relative to the spaceship the speed of A is 2 m/s and that of B is 1 m/s. A is carrying a bag of mass 5 Kg with him. To avoid collision with B A throws the bag with a speed v relative to the spaceship towards B catches it. Find the minimum value of v.
Physics
1 answer:
Keith_Richards [3.2K]3 months ago
7 0

The answer is:

V=14m/s

Details are as follows:

According to the problem, we have

The combined mass of A and B is 60kg

A's speed is 2m/s

B's speed is 1m/s

The mass of the bag is 5kg

Typically, the momentum of astronaut A along with the bag is defined by

M_A=(60+5)*2

M_A=130kgm/s

To prevent a collision, astronaut A should maintain a speed that is either equal to or less than astronaut B's speed

Thus, the minimum speed astronaut A should achieve corresponds to that of astronaut B, which is 1

Consequently,

130=(60*1)=(5*v)

V=14m/s

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Explanation:

Data

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Process

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1 gal ---------------- 3.78 l

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2.- Convert liters to milliliters

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Formula

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