25.82 m/s
Explanation:
Given:
Force applied by the baseball player; F = 100 N
Distance the ball travels; d = 0.5 m
Mass of the ball; m = 0.15 kg
To find the velocity at which the ball is released, we will equate the work done with the kinetic energy involved.
It's important to recognize that work done reflects the energy the baseball player has used. Thus, the relationship can be represented as follows:
F × d = ½mv²
100 × 0.5 = ½ × 0.15 × v²
Solving gives:
v² = (2 × 100 × 0.5) / 0.15
v² = 666.67
v = √666.67
v = 25.82 m/s.
Answer:
0.000047N
Explanation:
We know that
intensity (I) = P/ A
Where
P= power
A= Area
Thus, the power absorbed can be calculated as:
Power = Intensity x Area
This equals = 1.4 x 10^3 x(10)
Thus,
14000 Watts = 14 kWatt
However, the radiation pressure can be defined as
time-averaged intensity divided by the speed of light in a vacuum
So,
P = (1.4 x 1000)/c
Also,
F= P x A
Thus,
((1.4 x 1000)/(3 x10^8)) x 10
This results in
=0.000046666N
Rounded to two significant figures gives us
=0.000047 N
The result is 70.5 km/h. It seems the question is somewhat vague, but you're inquiring about the x-component of the helicopter's velocity. The x and y components can be calculated using sine and cosine ratios. The sine ratio connects the y-component with the overall velocity as follows: sin(angle) = y-component of velocity / velocity. Meanwhile, the cosine ratio relates the x-component to the velocity: cos(angle) = x-component of velocity / velocity. Given that you have both the angle and the velocity, and need to determine the x-component, you should apply the cosine ratio: cos(35°) = x-component / 86.0 km/h => x-component = 86.0 km/h * cos(35°) = 70.5 km/h.
