A sled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 N. The force of friction acting on the sled is
2.4 N. The free-body diagram shows the forces acting on the sled.
What is the acceleration of the sled and the normal force acting on it, to the nearest tenth?
1) a = 1.3 m/s2; FN = 63.1 N
2) a = 1.6 m/s2; FN = 65.6 N
3) a = 1.9 m/s2; FN = 93.7 N
4) a = 2.2 m/s2; FN = 78.4 N
What is the acceleration of the sled and the normal force acting on it, to the nearest tenth?
1) a = 1.3 m/s2; FN = 63.1 N
2) a = 1.6 m/s2; FN = 65.6 N
3) a = 1.9 m/s2; FN = 93.7 N
4) a = 2.2 m/s2; FN = 78.4 N
2 answers:
According to the problem, the sled has a mass of 8 kg.
The frictional force is quantified as 2.4 N.
A force of 20 N was applied to the sled at an angle of
.
When resolving the force into both horizontal and vertical components, we arrive at -
and
.
Here, identifies the horizontal component while
indicates the vertical component.
.
Likewise, for .
The free body diagram shows that the sum of the vertical forces amounts to zero since there’s no vertical movement.
Consequently, we can express it as , where g symbolizes the acceleration due to gravity.
Thus, .
Consequently, , and we recognize that the value of g is 9.8 m/s^2.
This leads to a normal force of = 63.1 N.
The net movement of the sled is in the forward direction.
Hence, as acceleration of the sled is symbolized as .
We can conclude that .
Finally, .
Thus, option A is correct.
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