Respuesta:
Opción e
Explicación:
La Ley de Gravitación Universal indica que toda masa puntual atrae a otra masa puntual en el universo con una fuerza que se dirige en línea recta entre los centros de masa de ambos, siendo esta fuerza proporcional a las masas de los objetos y inversamente proporcional a su separación. Esta fuerza atractiva siempre es dirigida del uno hacia el otro. La ley es aplicable a objetos de cualquier masa, sin importar su tamaño. Dos objetos grandes pueden ser considerados masas puntuales si la distancia entre ellos es considerablemente mayor que sus dimensiones o si presentan simetría esférica. En tales casos, la masa de cada objeto puede ser modelada como una masa puntual en su centro de masa.
La misma fuerza actúa sobre ambas bolas.
through the Doppler effect. The formula for apparent frequency is derived as F apparent = F real x (Vair ± Vobserver) / (Vair ± Vsource). In this scenario, should the observer move towards the source—place a positive sign in the numerator and a negative in the denominator. Since the observer approaches the wall, we apply the formula to derive the necessary speed.
No one is going to handle that for a mere 5 points lol.
Response:
C. vx
F. ax
G. ay
Clarification:
The projectile follows a curved trajectory toward the ground, causing changes in x and y positions.
Since there is no external force acting in the x-direction, the acceleration in x remains at zero. Consequently, ax and vx remain unchanged.
The projectile is subject to the force of gravity, directed downwards, leading to an increase in its velocity due to the rise in its y-component.
Meanwhile, the y-component of acceleration remains constant due to gravitational acceleration.
Answer: Tension = 47.8N, Δx = 11.5×
m.
Tension = 95.6N, Δx = 15.4×
m
Explanation: The speed of a wave on a string under tension can be determined using the following:
denotes tension (N)
μ refers to linear density (kg/m)
Calculating the velocity:
0.0935 m/s
Distance a pulse traveled in 1.23ms:
Δx = 11.5×
With a tension of 47.8N, the distance a pulse will cover is Δx = 11.5× m.
When tension is doubled:
|v| = 0.1252 m/s
Distance in the same time:
15.4×
With the increased tension, it moves 15.4× m
