The approximate answer is 6.84. Reasoning: (2.78^2 + 6.25^2)^(1/2) = 6.84 approx.
Answer:
Explanation:
According to the parameters provided,
mass of the clay lump, m₁ = 0.05 kg
initial velocity of the lump, u₁ = 12 m/s
mass of the cart, m₂ = 0.15 kg
initial speed of the cart, u₂ = 0
As the clay adheres to the cart, we have an inelastic collision scenario. Let v represent the combined speed of both the cart and lump post-collision. Given that momentum is conserved, we have:



The resultant speed is v = 3 m/s.
Thus, the final speed of both cart and lump following the collision is 3 m/s. This concludes the solution.
Answer: Her velocity magnitude (v) relative to the shore is 5.70 km/h.
Explanation:
Let Q be the speed of the boat, and P be the speed of the river flow.
R represents the resultant velocity combining boat velocity and river current.
According to vector addition using the law of triangles:

From the diagram:
P = 3.5 km/h, Q = 4.5 km/h




Therefore, her velocity magnitude relative to the shore is 5.70 km/h.