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Vera_Pavlovna
2 months ago
6

A pan containing 30 grams of water was allowed to cool from a temperature of 90.0 °C. If the amount of heat released is 1,500 jo

ules, what is the approximate final temperature of the water?
76 °C
78 °C
81 °C
82 °C
Chemistry
2 answers:
lions [2.9K]2 months ago
5 0
La temperatura final es de 78°C.
KiRa [2.9K]2 months ago
4 0
La opción B, 78.05 °C, representa la temperatura final aproximada del agua.
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A chalk company gets an order for 3000 boxes of chalk at the beginning of the school year, the largest order they have ever rece
VMariaS [2998]

The chalk production's efficiency is noted to be 82 %

To determine this efficiency, we utilize the formula,

% Efficiency=\frac{Actual yield (g)}{Theoretical yield (g)} *100

Finding the actual yield based on % efficiency and the theoretical yield:

82 %=\frac{Actual yield}{400,000 g} * 100

Actual yield = \frac{82 *400000 g}{100} = 32,800 g

Each box contains 145 grams of chalk

Total boxes = 32800 g *\frac{1 box}{145 g} = 2262 boxes

The chalk box company aims to produce 3000 boxes. However, with 82 % efficiency, they can only produce 2262 boxes, thus falling short of their target.

8 0
2 months ago
From this list, choose all of the ionic compounds. Check all that apply. View Available Hint(s) Check all that apply. POCl3 KOCH
lions [2927]

Answer: KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

Explanation:

Ionic compounds form when one atom transfers its valence electrons to another atom, resulting in partial opposite charges on the participating atoms, which creates a strong attractive force between them.

An ionic bond is typically established between a metal and a non-metal.

For instance, KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

Conversely, a covalent compound arises through the sharing of electrons among the atoms involved, where generally a non-metal bonds with the same or another non-metal.

For example, POCl_{3}, SOCl_{2} etc are all covalent compounds.

Therefore, we can affirm that KOCH_2CH_3, [tex]CH_3CH_2COONa, NaOH are indeed ionic compounds.

4 0
2 months ago
Which procedure cannot be performed on a hot plate, requiring a Bunsen burner instead
Tems11 [2777]

Answer: The process of heating a crucible to eliminate moisture from a hydrate.

Explanation:

The available choices are:

a. Heating a solvent to aid in the dissolution of a solute.

b. Heating a solid in isolation to remove moisture.

c. Bringing water to a boil for use in a water bath.

d. Heating a crucible to eliminate moisture from a hydrate.

Possible actions that can be done on a hot plate include:

a. Heating a solvent to assist a solute in dissolving.

b. Heating a solid in isolation to dry it.

c. Heating water to boiling for a water bath.

However, it's important to note that using a hot plate for heating a crucible to remove water from a hydrate is not advisable. Silica or ceramic materials are not meant to be heated on a hot plate.

Consequently, the correct procedure is heating a crucible to remove water from a hydrate.

4 0
3 months ago
Kayla owns a food truck that sells tacos and burritos. She sells each taco for $3 and each burrito for $7.25. Yesterday Kayla ma
VMariaS [2998]
They overcomplicated things with lots of words. Your initial equation deals with the revenue. I’ll denote tacos as x and burritos as y.
The first equation would be 3x + 7.25y = 595, given that you already have the prices but need the quantities. The second equation will reflect that double the burritos were sold compared to tacos, expressed as y = x + 2.
Hope this clarifies things. If you need further explanation, I can elaborate more.
6 0
3 months ago
What volume of co2 gas at 645 torr and 800. k could be produced by the decomposition of 45.0 g of caco3? caco3(s) → cao(s) + co2
KiRa [2933]
In the reaction: <span>caco3(s) → cao(s) + co2(g), it is evident that
1 mol (which is 100 g) of CaCO3 yields 1 mol (which is 44 g) of CO2
Now, the molarity of CaCO3 present in the reaction system is
</span>= \frac{weight of CaCO3 (g)}{gram molecular weight}
= \frac{45}{100} = 0.45 mol

Thus, 0.45 mol of CaCO3 leads to the formation of 0.45 mol of CO2.

According to the ideal gas equation, we have PV = nRT
V = \frac{nRT}{P}.
Considering P = 645 torr = 0.8487 atm (because 1 atm = 760 torr)
In that case, V = \frac{0.45 X 0.08206 X 800}{0.8487}

= 34.8 l
5 0
1 month ago
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