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AleksandrR
2 months ago
8

A chalk company gets an order for 3000 boxes of chalk at the beginning of the school year, the largest order they have ever rece

ived. Each box contains 145 grams of chalk. If the efficiency of their chalk production process is 82% and the theoretical yield of the production process is 400,000 grams, will they make their goal?
Chemistry
1 answer:
VMariaS [2.9K]2 months ago
8 0

The chalk production's efficiency is noted to be 82 %

To determine this efficiency, we utilize the formula,

% Efficiency=\frac{Actual yield (g)}{Theoretical yield (g)} *100

Finding the actual yield based on % efficiency and the theoretical yield:

82 %=\frac{Actual yield}{400,000 g} * 100

Actual yield = \frac{82 *400000 g}{100} = 32,800 g

Each box contains 145 grams of chalk

Total boxes = 32800 g *\frac{1 box}{145 g} = 2262 boxes

The chalk box company aims to produce 3000 boxes. However, with 82 % efficiency, they can only produce 2262 boxes, thus falling short of their target.

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27. How much energy is required to change 150.0 g of water from 10.0°C to 45.0°C? (Cwater =
Alekssandra [3086]

Answer:

The correct option is C. 21900.3. I calculated 21945 J, which makes option C closely aligned with my result.

Explanation:

Data

mass = 150 g

initial temperature T1 = 10°C

final temperature T2 = 45°C

Cw = 4.18 J/g°C

Formula

Q = mCΔT = mC(T2 - T1)

Substitution

Q = (150)(4.18)(45 - 10)

Simplification

Q = (150)(4.18)(35)

Result

Q = 21945 J

5 0
1 month ago
"A sample of silicon has an average atomic mass of 28.084amu. In the sample, there are three isotopic forms of silicon. About 92
lorasvet [2795]

Answer: The percentage abundance for _{14}^{30}\textrm{Si} isotope is 3.09 %.

Explanation:

The average atomic mass of an element is calculated by taking the sum of the masses of all isotopes weighted by their respective natural fractional abundances.

To compute average atomic mass, the following formula is applied:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

From the information provided:

Let the fractional abundance for _{14}^{28}\textrm{Si} isotope be 'x'

  • For _{14}^{28}\textrm{Si} isotope:

Mass of _{14}^{28}\textrm{Si} isotope = 27.9769 amu

Percentage abundance of _{14}^{28}\textrm{Si} isotope = 92.22 %

Fractional abundance for _{14}^{28}\textrm{Si} isotope = 0.9222

  • For _{14}^{29}\textrm{Si} isotope:

Mass of _{14}^{28}\textrm{Si} isotope = 28.9764 amu

Percentage abundance for _{14}^{28}\textrm{Si} isotope = 4.68%

Fractional abundance of _{14}^{28}\textrm{Si} isotope = 0.0468

  • For _{14}^{30}\textrm{Si} isotope:

Mass of _{14}^{30}\textrm{Si} isotope = 29.9737 amu

Fractional abundance for _{14}^{30}\textrm{Si} isotope = x

  • The average atomic mass of silicon is 28.084 amu

By inserting these values into equation 1, we derive:

28.084=[(27.9769\times 0.9222)+(28.9764\times 0.0468)+(29.9737\times x)]\\\\x=0.0309

To convert this fractional abundance into a percentage, multiply by 100:

\Rightarrow 0.0309\times 100=3.09\%

This shows that the percentage abundance for _{14}^{30}\textrm{Si} isotope is 3.09 %.

6 0
2 months ago
Select the option that correctly completes this statement: If the reaction takes place at a constant volume in a thermally insul
KiRa [2933]

Answer:

The temperature of the gas rises.

Explanation:

This is classified as an ISOCHORIC process where the volume remains unchanged. There is no work done by the system.

The gas only receives internal energy from the heat transferred to it from the surroundings.

In this situation, the pressure also increases.

8 0
2 months ago
A group of students is investigating how the addition of salt impacts the floatation of an egg in water. Four identical cups wer
VMariaS [2998]

Answer:

The dependent variable in this experiment is the egg's position above the water.

Explanation:

The dependent variable refers to the factor that is influenced by another variable.

On the other hand, the independent variable is what can be altered, affecting the dependent variable's outcome.

The controlled variable remains constant throughout the experiment.

In this setup, the amount of salt added acts as the independent variable, while the flotation level of the egg is the dependent variable, and the water volume in each cup represents the controlled variable.

7 0
1 month ago
Read 2 more answers
There is water on the pan of the scale as you measure the mass of an object. If you were to ignore the water, what would be the
castortr0y [3046]
Density is defined as the "mass per unit volume" of an object.

Thus, for an object weighing 100 grams with a volume of 100 milliliters, the density calculates to 100 grams / 100 ml.

When weighing the object, if there is water on the scale's surface, it will contribute additional weight, making the object seem heavier than its actual mass. Consequently, you might mistakenly conclude that the density is GREATER than it truly is.

For instance, if there were 5 ml of water on the scale, with water's density being 1 gram per milliliter (1 g/ml), it would add 5 grams to the object's weight. Using the previous example, the object's mass appears as 105 grams instead of 100 grams. Thus, you would calculate:

density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml

Thus, the effect on density would be to misleadingly suggest it is greater.

I hope this is helpful!

Best of luck
6 0
1 month ago
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