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Natasha2012
2 months ago
13

Determine Z and V for steam at 250°C and 1800 kPa by the following: (a) The truncated virial equation [Eq. (3.38)] with the foll

owing experimental values of virial coefficients: B = −152.5 cm3·mol−1 C = −5800 cm6·mol−2 (b) The truncated virial equation [Eq. (3.36)], with a value of B from the generalized Pitzer correlation [Eqs. (3.58)–(3.62)]. (c) The steam tables (App. E).
Chemistry
1 answer:
lorasvet [2.7K]2 months ago
3 0

Answer:

a) The values are: Fc = 4.15 N, Fi = 435.65 N, (F1)a = 640 N, and F2 = 239.6 N,b) Ha = 1863.75 N, nfs = 1, length = 11.8 mm

Explanation:

Given that:

γ= 9.5 kN/m³ = 9500N/m3 T_1

b = 6 inches = 0.1524 m

t = 0.0013 mm

d = 2 inches = 0.0508 m

n = 1750 rpm

\frac{PV}{RT} = 1 + \frac{B}{V} + \frac{C}{V^2}

152.5 \ cm^3 /molL = 9 ft = 2.7432 m cm^6/mol^2

Ks = 1.25

g = 9.81 m/s²

a)

\frac{1800*V}{8.314*10^3*523.15} = 1+ \frac{-152.5}{V} + \frac{-5800}{V^2}

4.138*10^{-4} \ V= 1+ \frac{-152.5}{V} + \frac{-5800}{V^2}

4.138*10^4 \ V ^3 = V^2 - 152.5 V - 5800 = 0

4.138*10^4 \ V ^3 - V^2 + 152.5 V + 5800 = 0

b)\frac{PV}{RT}

\frac{1800*2250.06}{8.314*10^3*523.15}

dip =

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