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Natasha2012
13 days ago
13

Determine Z and V for steam at 250°C and 1800 kPa by the following: (a) The truncated virial equation [Eq. (3.38)] with the foll

owing experimental values of virial coefficients: B = −152.5 cm3·mol−1 C = −5800 cm6·mol−2 (b) The truncated virial equation [Eq. (3.36)], with a value of B from the generalized Pitzer correlation [Eqs. (3.58)–(3.62)]. (c) The steam tables (App. E).
Chemistry
1 answer:
lorasvet [2.5K]13 days ago
3 0

Answer:

a) The values are: Fc = 4.15 N, Fi = 435.65 N, (F1)a = 640 N, and F2 = 239.6 N,b) Ha = 1863.75 N, nfs = 1, length = 11.8 mm

Explanation:

Given that:

γ= 9.5 kN/m³ = 9500N/m3 T_1

b = 6 inches = 0.1524 m

t = 0.0013 mm

d = 2 inches = 0.0508 m

n = 1750 rpm

\frac{PV}{RT} = 1 + \frac{B}{V} + \frac{C}{V^2}

152.5 \ cm^3 /molL = 9 ft = 2.7432 m cm^6/mol^2

Ks = 1.25

g = 9.81 m/s²

a)

\frac{1800*V}{8.314*10^3*523.15} = 1+ \frac{-152.5}{V} + \frac{-5800}{V^2}

4.138*10^{-4} \ V= 1+ \frac{-152.5}{V} + \frac{-5800}{V^2}

4.138*10^4 \ V ^3 = V^2 - 152.5 V - 5800 = 0

4.138*10^4 \ V ^3 - V^2 + 152.5 V + 5800 = 0

b)\frac{PV}{RT}

\frac{1800*2250.06}{8.314*10^3*523.15}

dip =

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Consider four beakers labeled A, B, C, and D, each containing an aqueous solution and a solid piece of metal. Identity the beake
castortr0y [2731]

Answer:

A Reaction

3. Pt(NO₃)₂(aq) + Cu(s)

4. Cr(s) + H₂SO₄(aq)

B Non Reaction

1. Mn(s) + Ca(NO₃)₂(aq)

2. KOH(aq) + Fe(s)

Y > Q > W > Z > X

Explanation:

The first task is determining if a reaction is set to take place according to the chemical equations outlined below.

1. Mn(s) + Ca(NO₃)₂(aq)

2. KOH(aq) + Fe(s)

3. Pt(NO₃)₂(aq) + Cu(s)

4. Cr(s) + H₂SO₄(aq)

Reactivity differs among elements; thus, they can be ordered by their reactivity levels.

1. Mn(s) + Ca(NO₃)₂(aq)

This reaction will not happen as Mn cannot replace Ca in its compound. A more reactive element typically displaces a less reactive one.

2. KOH(aq) + Fe(s)

The reaction is non-existent because Iron is less reactive compared to potassium, thus cannot replace it.

3. Pt(NO₃)₂(aq) + Cu(s)

Copper's reactivity exceeds that of platinum, allowing it to easily displace platinum. Therefore, this reaction will certainly occur.

4. Cr(s) + H₂SO₄(aq)

Chromium's position in the reactivity series is higher than that of hydrogen, enabling it to displace hydrogen in this compound. Consequently, this reaction will take place.

Based on the reactions

Q + W + Reaction occurs

Since a reaction occurs, element Q is more reactive, successfully displacing element W from the compound.

X + Z + No reaction

No reaction takes place since element X is less reactive than Z, and thus cannot displace Z.

W + Z + Reaction occurs

Here, element W is more reactive than Z, enabling it to displace Z from the compound.

Q + Y + Reaction occurs

In this instance, element Y is more reactive than Q, successfully displacing Q from its compound.

This results in the overall reactivity ranking as Y > Q > W > Z > X

3 0
25 days ago
The metallic radius of a lithium atom is 152 pm. What is the volume of a lithium atom in cubic meters?
eduard [2509]

Answer:

The calculated volume of a lithium atom is 1.47 X 10⁻²⁹ m³.

Explanation:

Assuming the atom's volume is spherical (though it’s actually more complex), the volume is mathematically represented by:

V=\frac{4}{3}\pi R^{3}----------------------------------------------------------------------------------------(Eq. 1)

Here, R corresponds to the lithium atom's radius. Since the radius is provided in picometers, we first convert it into meters.

R=(152pm )(1X10^{-12}\frac{m}{pm})

R = 1.52 X 10^{-10}m

Substituting this value into Eq.1 provides the desired result.

V=\frac{4}{3}\pi {1.52X10^{-10}}^{3}

V= 1.47 X 10⁻²⁹ m³

8 0
1 month ago
Ionic compounds are formed from ionic bonds, whereby an electron is transferred from the metal cation to the nonmetal anion. Ion
eduard [2509]
NaI
7 0
14 days ago
The volume of a gas at 6.0 atm is 2.5 L. What is the volume of the gas at 7.5 atm at the same temperature?
castortr0y [2731]

Greetings!

The result is:

The new volume is: 2L

Rationale:

Because the temperature remains constant, we can apply Boyle's Law to solve this issue.

Boyle's Law stipulates that:

P_{1}V_{1}=P_{2}V_{2}

Where,

P is the gas's pressure.

V is the gas's volume.

According to the information provided:

V_{1}=2.5L\\P_{1}=6.0atm\\P_{2}=7.5atm

Let's put the values into the equation:

2.5L*6.0atm=7.5atm*V_{2}

2.5L*6.0atm=7.5atm*V_{2}\\\\V_{2}=\frac{2.5L*6.0atm}{7.5atm}=\frac{15L.atm}{7.5atm}=2L

Consequently, the new volume is: 2L

Wishing you a lovely day!

7 0
1 month ago
What features of this model will help Armando answer the question?
lions [2649]

Answer:

The adjustable legs along with the sand table.

Note: The question is incomplete. The full question is presented below.

Using Models to Address Questions Regarding Systems

Armando’s class was examining images of rivers shaped by flowing water. Most rivers appeared wide and shallow, except for one, which was narrow and deep. The students theorized that this river's narrowness and depth are due to:

  • the steepness of the hill from which the water descends, or
  • the diminutive size of the sand grains the water flows through.

To explore the answer to the question of why this river is so narrow and deep, Armando created the model outlined below.

Explanation:

The model constructed by Armando will facilitate addressing the question due to specific features:

1. Adjustable leg - as one theory proposed by the class suggests that the steep hill affecting the water's path could be the reason for the river's dimensions, the adjustable legs are designed to be raised or lowered to alter the slope, allowing testing of this theory.

2. Sand table - this acts as the streambed. By modifying the size of the sand grains, students can examine the second hypothesis that smaller sand grains contribute to the river's narrowness and depth.

The outcomes of their experimentation will lead them to a conclusion.

5 0
1 month ago
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