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artcher
4 days ago
7

Bursitis can affect many joints and can be caused by a numerous sporting activities, such as cycling, tennis, and long-distance

running. Explain what bursitis is and what characteristics the mentioned sporting activities have in common?
Physics
2 answers:
serg [1.1K]4 days ago
8 0

Bursitis is characterized by discomfort in the joints. The bursae are the small sacs filled with fluid, providing cushioning between bones, tendons, joints, and muscles. When these bursae become inflamed, it is termed bursitis.

Common causes of bursitis include:

Tennis elbow: This condition is prevalent among golfers and tennis players, where repetitive elbow bending leads to inflammation and injury.

Clergyman's knee: Persistent kneeling can cause swelling and injury to the bursae around the knee.

Shoulder: Consistent overhead lifting or reaching can result in bursitis in the shoulder region.

Ankle: Walking excessively or wearing inappropriate footwear can cause ankle issues, often seen in ice skaters and athletes.

Buttocks: Prolonged sitting on hard surfaces, like riding a bicycle, may irritate the bursae in this area.

Hips: Hip bursitis can be common among runners and sprinters.

Thigh: Stretching may result in bursitis as well.

Yuliya22 [1.1K]4 days ago
6 0
Bursitis refers to the irritation or injury of the small fluid-filled sacs called bursae that are located around the joints. This condition can lead to pain during movement or when the affected area is pressed. Occasionally, a rash may also develop. Thank you for your inquiry; I trust this information will be beneficial.
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Refer to the diagram below.

Ignoring air resistance, use gravitational acceleration g = 9.8 m/s².

The pole vaulter drops with an initial vertical speed u = 0.
At impact with the pad, velocity v satisfies:
v² = 2 × (9.8 m/s²) × (4.2 m) = 82.32 (m/s)²
v = 9.037 m/s

As the pad compresses by 0.5 m to bring the vaulter to rest,
let the average acceleration (deceleration) be a m/s². Then:
0 = (9.037 m/s)² + 2 × a × 0.5 m
Solving for a gives:
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The two sides of the DNA double helix are connected by pairs of bases (adenine, thymine, cytosine, and guanine). Because of the
kicyunya [1025]

Answer:

Explanation:

An image of the bond resulting from the search is attached.

Consider the force directed towards thymine as negative.

For the O-H-N combination:

The resulting force from this combination is:

F=-F_{OH}+F_{ON}\\\\=\frac{Ke^2}{r^2}+\frac{Ke^2}{r'^2}\\\\=Ke^2(\frac{-1}{r^2}+\frac{1}{r'^2})\\\\=(9.0\times 10^9Nm^2/kg^2)(1.6\times 10^{-19}C)^2[\frac{1}{[(0.280-0.110)\times 10^{-9}m]^2}+\frac{1}{0.280\times 10^{-9}m)^2}]\\\\=-5.03354\times 10^{-9}N

In the case of the N-H-N combination:

The total force acting from this combination is:

F'=F_{NN}-F_{HN}\\\\=\frac{Ke^2}{r^2}-\frac{Ke^2}{r'^2}\\\\=Ke^2(\frac{-1}{r^2}+\frac{1}{r'^2})\\\\=(9.0\times 10^9Nm^2/kg^2)(1.6\times 10^{-19}C)^2[\frac{1}{[0.300\times 10^{-9}m]^2}-\frac{1}{((0300-0..110)\times 10^{-9})m)^2}]\\\\=-3.822\times 10^{-9}N

The force that thymine applies on adenine is:

F_{net}=F+F'\\\\=-5.03354\times 10^{-9}N-3.822\times 10^{-9}N\\\\=-8.8558\times 10^{-9}N

When rounded to three significant figures, the net force is 8.86\times 10^{-9}N

b)

The negative value indicates that the force is attractive, as it is aimed towards thymi.

c)

The force acting on the electron due to the proton is:

F=\frac{Ke^2}{r^2}\\\\=\frac{(9.0\times 10^9Nm^2/C^2)(1.6\times 10^{-9}C)^2}{(5.29\times 10^{-11}m)^2}\\\\=8.233\times 10^{-8}N

Since the electron and proton carry opposite charges, the force on the electron points towards the proton.

d)

The ratio of the above forces is:

\frac{F}{F_{net}}=\frac{8.233\times 10^{-8}N}{8.233\times 10^{-8}N}\\\\=9.3

Therefore, the bonding strength of the electron in the hydrogen atom is 9.3 times greater than the bonding force between adenine and thymine molecules.

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