Answer:
Explanation:
An image of the bond resulting from the search is attached.
Consider the force directed towards thymine as negative.
For the O-H-N combination:
The resulting force from this combination is:
![F=-F_{OH}+F_{ON}\\\\=\frac{Ke^2}{r^2}+\frac{Ke^2}{r'^2}\\\\=Ke^2(\frac{-1}{r^2}+\frac{1}{r'^2})\\\\=(9.0\times 10^9Nm^2/kg^2)(1.6\times 10^{-19}C)^2[\frac{1}{[(0.280-0.110)\times 10^{-9}m]^2}+\frac{1}{0.280\times 10^{-9}m)^2}]\\\\=-5.03354\times 10^{-9}N](https://tex.z-dn.net/?f=F%3D-F_%7BOH%7D%2BF_%7BON%7D%5C%5C%5C%5C%3D%5Cfrac%7BKe%5E2%7D%7Br%5E2%7D%2B%5Cfrac%7BKe%5E2%7D%7Br%27%5E2%7D%5C%5C%5C%5C%3DKe%5E2%28%5Cfrac%7B-1%7D%7Br%5E2%7D%2B%5Cfrac%7B1%7D%7Br%27%5E2%7D%29%5C%5C%5C%5C%3D%289.0%5Ctimes%2010%5E9Nm%5E2%2Fkg%5E2%29%281.6%5Ctimes%2010%5E%7B-19%7DC%29%5E2%5B%5Cfrac%7B1%7D%7B%5B%280.280-0.110%29%5Ctimes%2010%5E%7B-9%7Dm%5D%5E2%7D%2B%5Cfrac%7B1%7D%7B0.280%5Ctimes%2010%5E%7B-9%7Dm%29%5E2%7D%5D%5C%5C%5C%5C%3D-5.03354%5Ctimes%2010%5E%7B-9%7DN)
In the case of the N-H-N combination:
The total force acting from this combination is:
![F'=F_{NN}-F_{HN}\\\\=\frac{Ke^2}{r^2}-\frac{Ke^2}{r'^2}\\\\=Ke^2(\frac{-1}{r^2}+\frac{1}{r'^2})\\\\=(9.0\times 10^9Nm^2/kg^2)(1.6\times 10^{-19}C)^2[\frac{1}{[0.300\times 10^{-9}m]^2}-\frac{1}{((0300-0..110)\times 10^{-9})m)^2}]\\\\=-3.822\times 10^{-9}N](https://tex.z-dn.net/?f=F%27%3DF_%7BNN%7D-F_%7BHN%7D%5C%5C%5C%5C%3D%5Cfrac%7BKe%5E2%7D%7Br%5E2%7D-%5Cfrac%7BKe%5E2%7D%7Br%27%5E2%7D%5C%5C%5C%5C%3DKe%5E2%28%5Cfrac%7B-1%7D%7Br%5E2%7D%2B%5Cfrac%7B1%7D%7Br%27%5E2%7D%29%5C%5C%5C%5C%3D%289.0%5Ctimes%2010%5E9Nm%5E2%2Fkg%5E2%29%281.6%5Ctimes%2010%5E%7B-19%7DC%29%5E2%5B%5Cfrac%7B1%7D%7B%5B0.300%5Ctimes%2010%5E%7B-9%7Dm%5D%5E2%7D-%5Cfrac%7B1%7D%7B%28%280300-0..110%29%5Ctimes%2010%5E%7B-9%7D%29m%29%5E2%7D%5D%5C%5C%5C%5C%3D-3.822%5Ctimes%2010%5E%7B-9%7DN)
The force that thymine applies on adenine is:

When rounded to three significant figures, the net force is 
b)
The negative value indicates that the force is attractive, as it is aimed towards thymi.
c)
The force acting on the electron due to the proton is:

Since the electron and proton carry opposite charges, the force on the electron points towards the proton.
d)
The ratio of the above forces is:

Therefore, the bonding strength of the electron in the hydrogen atom is 9.3 times greater than the bonding force between adenine and thymine molecules.