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dangina
1 month ago
7

A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal. How much en

ergy was delivered to the circuit?
Physics
1 answer:
Yuliya22 [3.3K]1 month ago
7 0

Answer:

The energy delivered is E = 0.18 J

Explanation:

Given,

Battery voltage, V = 9 V

Charge in the circuit, Q = 20 mC

                                        = 20 x 10³ C

Energy supplied in the circuit can be computed as

E = Q V

E = 20 x 10⁻³ x 9

E =  180 x 10⁻³

E equals 0.18 J.

The energy delivered in the circuit is therefore E = 0.18 J

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Two experiments are performed on an object to determine how much the object resists a change in its state of motion while at res
inna [3103]

Answer:

The first experiment measures inertial mass, while the second experiment measures gravitational mass.

Explanation:

A student conducts two different experiments to observe resistance to changes in motion, both when at rest and in motion.

In the initial experiment, an object is forcefully pushed against a flat surface while its speed is tracked by a sensor. This setup involves work done against the object's inertia, identifying the mass as inertial mass.

Conversely, in the subsequent experiment, the object is lifted or thrown upward with an applied force and the speed is recorded. Here, the mass refers to gravitational mass, as the work performed combats gravity or the object's weight.

5 0
2 months ago
If a metal wire is 4m long and a force of 5000n causes it to stretch by 1mm, what is the strain?
serg [3582]

Answer:

2.5\cdot 10^{-4}

Explanation:

Strain is defined as the ratio of an object's dimensional change when subjected to a force:

S=\frac{\Delta L}{L_0}

where

\Delta L indicates the alteration in length of the object

L_0 signifies the object's initial length

In this case, we have L_0 = 4 m and \Delta L=1 mm=0.001 m, hence the strain is

S=\frac{\Delta L}{L_0}=\frac{0.001 m}{4 m}=2.5\cdot 10^{-4}


5 0
1 month ago
A ball rolls up a slope. At the end of three seconds its velocity is 20 cm/s; at the end of eight seconds its velocity is 0. Wha
serg [3582]

Answer:

a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}

Explanation:

Data provided

initial velocity v₀=20 cm/s at time t=3s

final velocity vf=0 at time t=8 s

Required

Average Acceleration for the interval from 3s to 8s

Solution

Acceleration can be defined as the first derivative of velocity concerning time

a_{acceleriation} =\frac{dv_{velocity}}{dt_{time}}\\a_{acceleriation} =\frac{v_{f}-v_{o} }{dt}\\ a_{acceleriation} =\frac{0-20cm/s }{8s-3s}\\ a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}

8 0
2 months ago
A plane takes off in san francisco at noon and flies toward the southeast. an hour later, it is 400 kilometers east and 300 kilo
Keith_Richards [3271]
This initial stage represents a right triangle. If the aircraft is positioned 400 km to the east and 300 km to the south of the origin while traveling in a straight path, you can form a right triangle with sides measuring 300, 400, and c. You might notice that these dimensions correspond to multiples of the Pythagorean triple 3, 4, 5, meaning that the length of c is 500 km. Alternatively, you would indicate
c^2 = 300^2+400^2 \\ c = 500.

For the second step, assuming I am correctly understanding "degrees south of east," it involves calculating the angle between the horizontal line indicating east and the trajectory of the aircraft. I created a diagram illustrating this (see attached). You could employ a trigonometric function related to one of the angles to find the solution. I selected
tan(C)= \frac{3}{4} \\ arctan( \frac{3}{4})=36.870. Therefore, I deduce that the angle is 37° south of east.

5 0
1 month ago
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