A student performs an experiment that involves the motion of a pendulum. The student attaches one end of a string to an object o

Answer:

h = 10 m

Explanation:

Given,

mass of the platform = 50 Kg

Kinetic energy = 5000 J

height from which the diver dove =?

Taking the acceleration due to gravity as 10 m/s²

Using the conservation of energy principle

Kinetic energy is transformed into potential energy

K.E = P.E

K.E = m g h

5000 = 50 x 10 x h

500 h = 5000

    h = 10 m

The height from which the diver dove is equal to h = 10 m

Answer:

The particle's energy in its ground state is E₁=1.5 eV.

Explanation:

For a particle with mass m in the nth energy level of an infinite square well potential of width L , the energy is given by:

In the ground state (n=1) and in the first excited state (n=2), where the energy is noted as E₂= 6.0 eV. Substituting into the above equation yields:

Thus, we can express the ground state's energy as:

Ultimately