answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nikitadnepr
23 hours ago
14

Four students measured the acceleration of gravity. The accepted value for their location is 9.78m/s2. Which student’s measureme

nt has the largest percent error?
A. Student 4: 9.61 m/s2
B. Student 3: 9.88 m/s2
C. Student 2: 9.79 m/s2
D. Student 1: 9.78 m/s2
Physics
1 answer:
Ostrovityanka [2.2K]23 hours ago
4 0
Upon comparison, it is evident that the student with the highest percent error is A. Student 4, who measured 9.61 m/s². Four students recorded the acceleration of gravity, with the accepted local value being 9.78 m/s². Now let's find out which student's measurement exhibited the greatest percent error.
You might be interested in
What is the number N0 of 99mTc atoms that must be present to have an activity of 15mCi?
Keith_Richards [2263]
Based on my findings, within a period of 2 hours, there are certain atoms remaining. N = N0 * 2^(-t/6.020) = N = N0 * 2^-0.33223 = 0.7943 N0 Thus, the quantity of atoms that undergo disintegration is N0 - N = N0 * (1 - 0.79430) = 0.2057 N0 This must equate to 15 mCi = 15 * 3.7 * 10^7 = 5.55 * 10^8 atoms N0 = 5.55 * 10^8 / 0.2057 = 2.698 * 10^9 atoms Consequently, 2.698 * 10^9 atoms represents the value of N0.
4 0
25 days ago
The drawing shows an adiabatically isolated cylinder that is divided initially into two identical parts by an adiabatic partitio
Yuliya22 [2438]

Answer:

the temperature on the left side is 1.48 times greater than that on the right

Explanation:

GIVEN DATA:

\gamma = 5/3

T1 = 525 K

T2 = 275 K

It is known that

P_1 = \frac{nRT_1}{v}

P_2 = \frac{nrT_2}{v}

n and v are constant on both sides. Therefore we have

\frac{P_1}{P_2} = \frac{T_1}{T_2} = \frac{525}{275} = \frac{21}{11}

P_1 = \frac{21}{11} P_2..............1

let the final pressure be P and the temperature T_1 {f} and T_2 {f}

P_1^{1-\gamma} T_1^{\gamma} = P^{1 - \gamma}T_1 {f}^{\gamma}

P_1^{-2/3} T_1^{5/3} = P^{-2/3} T_1 {f}^{5/3}..................2

similarly

P_2^{-2/3} T_2^{5/3} = P^{-2/3} T_2 {f}^{5/3}.............3

divide equation (2) by equation (3)

\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}

T_1 {f} = 1.48 T_2 {f}

thus, the left side temperature equals 1.48 times the right side temperature

6 0
12 days ago
In space, astronauts don’t have gravity to keep them in place. That makes doing even simple tasks difficult. Gene Cernan was the
Keith_Richards [2263]

Newton's First Law: A body remains in its current state of motion or at rest unless a force acts upon it.

Newton's Second Law: Motion changes are proportional to the applied force and oriented in the same direction.

Newton's Third Law: Every action has a corresponding and opposite reaction.

Tasks that would be challenging to perform in orbit include:

-operating a valve

-navigating on foot

-attempting to take a shower

-remaining still


4 0
7 days ago
Read 2 more answers
A 5 kg block moves with a constant speed of 10 ms to the right on a smooth surface where frictional forces are considered to be
Yuliya22 [2438]

Answer:

The work done, W = 19.6 J

Explanation:

It’s provided that

The mass of the block, m = 5 kg

The velocity of the block, v = 10 m/s

The coefficient of kinetic friction between the block and rough surface is 0.2

Distance traveled by the block, d = 2 m

As the block traverses the rough section, it loses energy equal to the work done by the kinetic energy.

W=\mu_kmgd

W=0.2\times 5\times 9.8\times 2

W = 19.6 J

Thus, the change in kinetic energy of the block moving through the rough section is 19.6 J. Consequently, this is the required answer.

5 0
4 days ago
Read 2 more answers
What is the minimum frequency of light necessary to emit electrons from titanium via the photoelectric effect?
kicyunya [2264]

<span>E = h x f </span>

<span>Thus: </span>

<span>f = E / h </span>
<span>f = 4.41•10^-19 / 6.62•10^-34 </span>
<span>f = 6.66•10^14 Hz (s^-1) </span>


<span>b/ What is the wavelength of this light? </span>
<span>------------------------------ </span>

<span>λ = c / f </span>
<span>λ = 3•10^8 / 6.66•10^14 </span>
<span>λ = 4.50•10^-7 m </span>
4 0
28 days ago
Read 2 more answers
Other questions:
  • In an amusement park rocket ride, cars are suspended from 3.40-m cables attached to rotating arms at a distance of 5.90 m from t
    10·1 answer
  • At one instant of time a rocket is traveling in outer space at 2500m/s and is exhausting fuel at a rate of 100 kg/s. If the spee
    6·1 answer
  • Is the electric potential energy of a particle with charge q the same at all points on an equipotential surface?
    13·1 answer
  • A thin electrical heating element provides a uniform heat flux qo" to the outer surface of a duct through which air flows. The d
    7·1 answer
  • For years, space travel was believed to be impossible because there was nothing there Rockets could push off in space in order t
    8·1 answer
  • A tube with a cap on one end, but open at the other end, produces a standing wave whose fundamental frequency is 130.8 Hz. The s
    11·1 answer
  • A constant-velocity horizontal water jet from a stationary nozzle impinges normally on a vertical flat plate that rides on a nea
    10·1 answer
  • An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmoni
    14·1 answer
  • A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of
    11·1 answer
  • A 1500 kg car enters a section of curved road in the horizontal plane and slows down at a uniform rate from a speed of 100 km/h
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!