Four students measured the acceleration of gravity. The accepted value for their location is 9.78m/s2. Which student’s measureme

Answer:

4.32 kg.m/s

Explanation:

The 2.4 kg stone moves at a speed of 3.6 m/s with an angle of 30 degrees from the x+ direction towards y+. The momentum's y-component is calculated by multiplying its mass with its velocity in the y-direction.

Answer:

θ=142.9°

Explanation:

d=1 *r

angle ϕ= 37.1°

The line between the pebble and the target must be tangential to a circle, hence

cos(180-ϕ-θ)==

Therefore, θ=180-ϕ-

  θ= 180-37.1-0

  θ=142.9°

 

9.375 Nm. The torque is calculated using the formula τ = Frsin∅, where F is the applied force (newton), r is the radius (in meters), and ∅ is the angle formed with the bar. With F= 25N, r = 0.75m, and ∅ = 30°, the torque on the bar results in τ  = 25*0.75*sin30° = 25*0.75*0.5, yielding τ = 9.375 Nm.

12 degrees = (π / 180) x 12 radians =.2093 radians; the position of the third bright fringe is determined as 3λ D/d, where λ represents the light wavelength, D is the distance to the screen, and d is the slit separation. Thus, the equation results in 3λ D/d = 30 x 10⁻², and from the angular separation, we deduce 3λ/d =.2093. Substituting the two equations, we find.2093 D = 30 x 10⁻², leading to D = 30 x 10⁻² /.2093 = 1.43 m.