answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
larisa86
8 days ago
11

If you are lying down and stand up quickly, you can get dizzy or feel faint. This is because the blood vessels don't have time t

o expand to compensate for the blood pressure drop. If your brain is 0.4 m higher than your heart when you are standing, how much lower is your blood pressure at your brain than it is at your heart
Physics
1 answer:
Sav [2.2K]8 days ago
3 0

Complete Question

Standing up quickly from a lying position may lead to dizziness or faintness. This occurs because the blood vessels cannot dilate sufficiently to adjust for the sudden drop in blood pressure. If your brain is 0.4 m above your heart when you are upright, what is the difference in blood pressure between these two points? The density of blood plasma is approximately 1025 kg/m3, and the typical systolic blood pressure at the heart is 120 mm of Hg (which is equal to 0.16 atm, 16 kP, or 1.6 × 104 N/m2).

Answer:

The pressure at the brain is P_b = 89.872 \ mm \ of \ Hg

Explanation:

It is generally represented mathematically as

                  P = \rho gh

By substituting 1025 kg/m^3 for \rho (the density), 9.8 m/s^2 for g (acceleration due to gravity), and 0.4m for h (height)

We can express the pressure difference between the brain and the heart as

              P = 1025 * 9.8 *0.4

                  = 4018 N/m^2

The blood pressure at the heart is given as

               P_h=120 mm of Hg = 120 * 133 = 1.59*10^3Pa

Now, the calculated pressure at the brain becomes

                 P_b = P_h - P

                     = 1.596*10^4 - 4018

                     = 11982 N/m^2

                      P_b= \frac{11982}{133} = 89.872 \ mm \ of \ Hg

   

     

You might be interested in
A bowling pin is thrown vertically upward such that it rotates as it moves through the air, as shown in the figure. Initially, t
Ostrovityanka [2208]

Answer:

Explanation:

The equation used to determine the maximum height of the bowling pin during its trajectory is given by;

H = u²/2g

where u, the initial speed/velocity, equals 10m/s

g stands for gravitational acceleration = 9.81m/s²

Substituting in the values gives us

H = 10²/2(9.81)

H = 100/19.62

Consequently, the highest point of the bowling pin's center of mass is approximately 5.0m.

3 0
1 month ago
The amount of kinetic energy an object has depends on its mass and its speed. Rank the following sets of oranges and cantaloupes
Sav [2230]

mass₃<mass₁=mass₅<mass₂=mass₄

Explanation:

Data points:-

1. mass:  m      speed: v

2. mass: 4 m   speed: v

3. mass: 2 m   speed: ¼ v

4. mass: 4 m   speed: v

5. mass: 4 m   speed: ½ v

We know that the formula for Kinetic energy (KE) is ½ mv²

Where m represents the mass of the object

           v represents the object's velocity

<psubstituting the="" given="" values="" for="" mass="" and="" speed="" from="" previous="" data:="">

The KE of Body 1(mass₁) = ½*m*v²             = mv²/2

KE of Body 2(mass₂) = ½*4m*v²         = 2mv²

KE of Body 3(mass₃) = ½*2m*(1/4v)²  =  mv²/16

KE of Body 4(mass₄) = ½*4m*v ²        =  2mv ²

KE of Body 5(mass₅) = ½*4m*(1/2v)²  =   mv²/2

</psubstituting>
6 0
17 days ago
A large box of mass m sits on a horizontal floor. You attach a lightweight rope to this box, hold the rope at an angle θ above t
inna [2210]

Answer:

The answer to the specified question will be "\mu_{s}=\frac{T_{m}Cos\theta}{M_{g}-T_{m}Sin\theta}".

Explanation:

Referring to the question,

\sum F_{x}

⇒  TCos \theta-F_{s}=0

⇒  T_{m}Cos \theta =F_{s}...(equation 1)

\sum F_{y}

⇒  TSin \theta+F_{N}=m_{g}

⇒  M_{g}-TSin \theta=F_{N}...(equation 2)

Now,

From equation 1 and equation 2, we conclude

⇒  T_{m} Cos \theta = \mu_{s}F_{N}

By substituting the value of F_{N}, we derive

⇒  T_{m} Cos\theta = \mu_{s}(M_{g}-T_{m}Sin \theta)

⇒  \mu_{s}=\frac{T_{m}Cos\theta}{M_{g}-T_{m}Sin\theta}

4 0
16 days ago
When a vertical beam of light passes through a transparent medium, the rate at which its intensity I decreases is proportional t
Keith_Richards [2263]

Response:

The intensity of light 18 feet underwater is about 0.02%

Clarification:

Employing Lambert's law

Let dI / dt = kI, where k is a proportionality factor, I represents the intensity of incident light, and t indicates the thickness of the medium

Then dI / I = kdt

Taking logarithms,

ln(I) = kt + ln C

I = Ce^kt

At t=0, I=I(0) implies C=I(0)

I = I(0)e^kt

At t=3 & I=0.25I(0), we find 0.25=e^3k

Solving for k gives k = ln(0.25)/3

k = -1.386/3

k = -0.4621

I = I(0)e^(-0.4621t)

I(18) = I(0)e^(-0.4621*18)

I(18) = 0.00024413I(0)

The intensity of light 18 feet underwater is about 0.2%

3 0
19 days ago
The 8 kg block is then released and accelerates to the right, toward the 2 kg block. The surface is rough and the coefficient of
kicyunya [2264]
3.258 m/s Explanation: The spring constant is assumed to be 263 N/m and the displacement of the spring is also assumed to be 0.7 m; the coefficient of friction between blocks is 0.4. The energy stored in the spring is described by . Given the conservation of energy in the system, the speed of the 8 kg block just prior to collision is 3.258 m/s.
7 0
4 days ago
Other questions:
  • To avoid an accident, a driver steps on the brakes to stop a 1000-kg car traveling at 65km/h. if the braking distance is 35 m, h
    7·1 answer
  • A 2.50-kg textbook is forced against a horizontal spring of negligible mass and force constant 250 N/m, compressing the spring a
    10·1 answer
  • Describe a well-known hypothesis that was discarded because it was found to be untrue.earth-centered model of the universe. the
    6·1 answer
  • Daring Darless wishes to cross the Grand Canyon of the Snake River by being shot from a cannon. She wishes to be launched at 65
    14·1 answer
  • In the demolition of an old building, a 1,300 kg wrecking ball hits the building at 1.07 m/s2. Calculate the amount of force at
    15·2 answers
  • A floating balloon can be formed when the substance helium is released from a compressed container into a flat rubber balloon. T
    9·2 answers
  • Falling raindrops frequently develop electric charges. Does this create noticeable forces between the droplets? Suppose two 1.8
    6·2 answers
  • A lens of focal length 15.0 cm is held 10.0 cm from a page (the object ). Find the magnification .
    5·1 answer
  • While an emf source supplies energy to a circuit, that energy is dissipated when the current passes through resistance. In deali
    12·1 answer
  • A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!