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fenix001
18 days ago
14

Consider the general reversible reaction. Lower A upper A plus lower B upper B double-headed arrow lower C upper C plus Lower d

upper D. What is the equilibrium constant expression for the given system? K e q equals StartFraction lowercase C StartBracket upper C EndBracket lowercase d StartBracket upper D EndBracket over lowercase A StartBracket upper A EndBracket lowercase B StartBracket upper B EndBracket EndFraction. K e q equals StartFraction StartBracket upper C EndBracket StartBracket upper D EndBracket over StartBracket upper A EndBracket StartBracket upper B EndBracket EndFraction. K e q equals StartFraction StartBracket upper A EndBracket superscript lower a StartBracket upper B EndBracket superscript lower b over StartBracket upper C EndBracket superscript lower c StartBracket upper D EndBracket superscript lower D EndFraction. K e q equals StartFraction StartBracket upper C EndBracket superscript lower c StartBracket upper D EndBracket superscript lower D over StartBracket upper A EndBracket superscript lower a StartBracket upper B EndBracket superscript lower b EndFraction.
Chemistry
2 answers:
Alekssandra [2.7K]18 days ago
6 0
K e q equals StartFraction StartBracket upper C EndBracket superscript lower c StartBracket upper D EndBracket superscript lower D over StartBracket upper A EndBracket superscript lower a StartBracket upper B EndBracket superscript lower b EndFraction. To clarify the query, let's express the components in the format of a standard chemical reaction equation: aA + bB ⇄cC + dD. We should bear in mind that the equilibrium constant, commonly represented as Keq, is defined as the ratio of the product concentrations of products raised to the power of their respective molar coefficients to that of reactants raised to their respective molar coefficients. Hence, based on the previous description, we can assert that Keq= [C]^c [D]^d / [A]^a [B]^b. This is expressed in words in the answer provided above.
lions [2.6K]18 days ago
4 0
Keq= [C]^c [D]^d / [A]^a [B]^b.
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