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Vlada
20 days ago
13

The maximum acceptable concentration of fluoride in tap water is 1.5mg/L. Express this concentration in ppm. Then figure what vo

lume of tap water contains 1.0 g of fluroide
Chemistry
1 answer:
KiRa [2.7K]20 days ago
3 0
The maximum permissible fluoride concentration in tap water is established at 1.5 mg/L. Notably, 1 mg/L corresponds to 1 part per million (ppm). In converting 1.5 mg/L to ppm, it is evident that the acceptable fluoride concentration in tap water is thus 1.5 ppm. To determine the volume of tap water containing 1.0 g of fluoride, we must first convert 1.0 g to mg. Since the fluoride concentration in tap water is 1.5 mg/L, calculating the volume gives us the value: Volume = 1000 mg divided by 1.5 mg/L, leading to approximately 667 mL of tap water.
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If 3.8 kcal is released by combustion of each gram of glucose, how many kilocalories are released by the combustion of 1.50 mol
castortr0y [2727]
684 kcal. One mole of glucose weighs roughly 180g. Given that 1g of glucose releases 3.8 kcal, we calculate for 1 mole of glucose: 180g -> 180g * 3.8 kcal/g = 684 kcal.
7 0
15 days ago
Neither dry soil nor pure water conducts electricity. But wet soil will conduct electricity. Explain why this happens?
Alekssandra [2698]

Pure water lacks sufficient ions to conduct electricity. However, when metals like iron, zinc, and copper are present in moist soil, they can instigate electrolysis, which necessitates excess energy due to limited water's self-ionization. Consequently, wet soil can carry current as long as there are positive and negative ions. Water ions travel from the anode (positive side) to the cathode (negative side) to be oxidized and generate electricity.

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4 0
12 days ago
41. A 13.0% solution of K2CO3 by mass has a density of 1.09 g/cm3. Calculate the molality of the solution.
lions [2639]

Answer:

The molality of the solution is 1.08 m.

Explanation:

First, determine the mass of the solvent.

A 13% solution by mass indicates that 13 grams are found in every 100 grams of solution.

Thus, solution mass = solute mass + solvent mass

100 g = 13 g + solvent mass

Therefore, solvent mass = 100 g - 13 g → 87 g

Next, we calculate the moles of solute (mass / molar mass):

13 g / 138.2 g/mol = 0.094 moles

Finally, to find the molality, which is the moles of solute per 1 kg of solvent (mol/kg), we convert the solvent mass to kg:

87 g. 1 kg / 1000 g = 0.087 kg

Then, molality → 0.094 mol / 0.087 kg = 1.08 m

5 0
1 month ago
Suppose a student needs to standardize a sodium thiosulfate, Na2S2O3,Na2S2O3, solution for a titration experiment. To do so, he
alisha [2704]

Answer:

0.133

Explanation:

The reaction that occurs between KIO3 and KI in an acidic medium is described as

IO3⁻ +5I⁻ +6h⁺ → 3I₂ + 3H₂O

I₂ subsequently reacts with sodium thiosulfate

NaS₂O₃  → 2Na⁺ + S₂O₃²⁻

The overall reaction can be summarized as

IO⁻₃ + 6H⁺ + 6S₂O₃³⁻ → I⁻ + 3S₄O₆²⁻ + 3H₂O

The mole of KIO₃

is computed using molarity multiplied by volume

\frac{0.02mol}{L} *0.01L

which equals 0.00002mol

One mole of KIO₃ reacts with 6 moles of S₂O₃²⁻

which gives 2x6x10⁻⁵

= 0.00012 mol

The volume is 0.90 ml

1 ml equals 0.001L

0.90ML  is 0.0009L

To find concentration,

molarity/volume

= 0.00012/0.0009

= 0.133m

5 0
13 days ago
Which statement is true about molarity and percent by mass?
Anarel [2593]

Answer: The correct choice is that they represent different concentration units.

Explanation:

Molarity: Defined as the quantity of solute moles in a liter of solution.

Molarity formula:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution in liters}}

Mass percent: Represents the mass of solute relative to the total mass of the solution.

Mass percent formula:

\text{Mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

This demonstrates that they are distinct units of concentration.

5 0
1 month ago
Read 2 more answers
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