Write a conclusion to this lab in which you discuss when a person on a roller coaster ride would have sensations of weightlessne

Flow rate calculations yield 220 cans, each with a volume of 0.355 l, leading to 78.1 l/min or 1.3 l/s or 0.0013 m³/s.

At Point 2:
A2 = 8 cm² = 0.0008 m²
V2 = Flow rate/A2 = 0.0013/0.0008 = 1.625 m/s
P1 = 152 kPa = 152000 Pa

At Point 1:
A1 = 2 cm² = 0.0002 m²
V1 = Flow rate/A1 = 0.0013/0.0002 = 6.5 m/s
P1 =?
Height = 1.35 m

Using Bernoulli’s principle;
P2 + 1/2 * V2² / density = P1 + 1/2 * V1² / density + density * gravitational acceleration * height
=> 152000 + 0.5 * (1.625)² * 1000 = P1 + 0.5 * (6.5)² * 1000 + (1000 * 9.81 * 1.35)
=> 153320.31 = P1 + 34368.5
=> P1 = 1533210.31 - 34368.5 = 118951.81 Pa = 118.95 kPa

Answer:

The work done, W = 19.6 J

Explanation:

It’s provided that

The mass of the block, m = 5 kg

The velocity of the block, v = 10 m/s

The coefficient of kinetic friction between the block and rough surface is 0.2

Distance traveled by the block, d = 2 m

As the block traverses the rough section, it loses energy equal to the work done by the kinetic energy.

W = 19.6 J

Thus, the change in kinetic energy of the block moving through the rough section is 19.6 J. Consequently, this is the required answer.

The angle formed with the positive x-axis is 120 degrees. We can assume that this angle is determined in a counterclockwise direction from the positive x-axis. The x-component of the vector can be calculated as: x-component = 10 cos(120) = -5. The vector's y-component is determined as: y-component = 10 sin(120) = 8.66. The x-component equates to -5 while the y-component equals 8.66.

The response is 176 minutes. The translation of 456 g equals 0.456 kg. The specific heat of ice is 2093 J kg⁻¹, used to calculate heat required for a 25-degree rise, determined by mass multiplied by specific heat and temperature increase. The necessary calculations yield a total heat load of 176164 J. Finally, by dividing heat required by heat supply rate, we ascertain that it will take approximately 176.16 minutes.

Answer:

a) The jogger's acceleration is 1.5 m/s²

b) The car's acceleration is also 1.5 m/s²

c) Yes, the car covers a distance 76 m greater than the jogger.

Explanation:

a) Acceleration is the change in velocity over a given time interval:

a = (final velocity - initial velocity) / time

For the jogger:

a = (3.0 m/s - 0 m/s) / 2.0 s = 1.5 m/s²

b) For the car:

a = (41.0 m/s - 38.0 m/s) / 2.0 s = 1.5 m/s²

c) To find how far the car has traveled after 2 seconds, use the formula for position under acceleration along a straight path:

x = x₀ + v₀ t + ½ a t²

where

x = position at time t

x₀ = initial position

v₀ = initial velocity

t = elapsed time

a = acceleration

Assuming x₀ = 0 (origin at car's starting point):

x = 38.0 m/s × 2 s + ½ × 1.5 m/s² × (2.0 s)²

x = 79 m

Similarly, position of the jogger after 2 seconds is:

x = 0 m/s × 2 s + ½ × 1.5 m/s² × (2.0 s)² = 3 m

The difference traveled by the car compared to the jogger is 79 m - 3 m = 76 m