answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tpy6a
3 months ago
9

Write a conclusion to this lab in which you discuss when a person on a roller coaster ride would have sensations of weightlessne

ss and when they would have sensations of weightiness. In your discussion, talk about accelerations and forces. Then finish off your conclusion by using Newton's second law to explain why such accelerations and force conditions cause these sensations.
Physics
1 answer:
Yuliya22 [3.3K]3 months ago
3 0

Answer:

the lower segment of the curve     N = M (g + v² / r)

the upper segment of the curve          N = m (v² / r - g)

Explanation:

A roller coaster features an extended ascent that enables the car to gain gravitational potential energy, which converts into kinetic energy, leading to a curve experience. In these curves, there are two sections: the lower section where riders experience heightened weight and the upper section where they feel lighter or weightless.

These feelings can be analyzed through Newton's second law; we will apply it to the lower section of the curve

         N - W = m a

the acceleration here is centripetal

        a = v² / r

substituting these values

        N = mg + m v² / r

        N = M (g + v² / r)

At this point, the perceived weight escalates due to the square of the body's speed, resulting in a significant feeling of heaviness.

In the top section of the curve, gravitational force still acts downward, and the normal force, which reacts to the surface, also pushes downwards, while the centripetal acceleration heads toward the curve's center, also directed vertically downward

        -N - W = -m a

         N = ma - W

         N = m (v² / r - g)

In this instance, the normal force, which generates the weight sensation, diminishes, leading to the perception of decreased weight. When v² / r equals g, the feeling of weightlessness becomes complete.

You might be interested in
A 5.00-A current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. Copper has 8.5 * 1028 free ele
Maru [3345]

Answer:

a)n= 3.125 x 10^{19 electrones.

b)J= 1.515 x 10^{6 A/m²

c)V_{d =1.114 x 10^{4m/s

d) ver explicación

Explanation:

La corriente 'I' = 5A =>5C/s

diámetro 'd'= 2.05 x 10^{-3 m

radio 'r' = d/2 => 1.025 x 10^{-3 m

número de electrones 'n'= 8.5 x 10^{28}

a) La cantidad de electrones que pasan por la bombilla cada segundo se determina mediante:

I= Q/t

Q= I x t => 5 x 1

Q= 5C

Como sabemos que: Q= ne

donde e es la carga del electrón, es decir, 1.6 x 10^{-19C

n= Q/e => 5/ 1.6 x 10^{-19

n= 3.125 x 10^{19 electrones.

b) La densidad de corriente 'J' en el cable se calcula como

J= I/A => I/πr²

J= 5 / (3.14 x (1.025x 10^{-3)²)

J= 1.515 x 10^{6 A/m²

c) La velocidad típica 'V_{d' de un electrón se expresa como:

V_{d = \frac{J}{n|q|}

    =1.515 x 10^{6 / 8.5 x 10^{28} x |-1.6 x 10^{-19|

V_{d =1.114 x 10^{4m/s

d) De acuerdo con estas ecuaciones,

J= I/A

V_{d = \frac{J}{n|q|} =\frac{I}{nA|q|}

Si utilizaras un cable de doble diámetro, ¿cuáles de las respuestas anteriores cambiarían? ¿Aumentarían o disminuirían?

5 0
4 months ago
Read 2 more answers
two forces P and Q pass through a point A which is 4 ft to the right of and 3 ft above a moment center O. force P is 200 lb dire
Sav [3153]
Thanks for asking your question here. I hope this response provides clarity. Feel free to ask additional questions. The moment resulting from the two forces about point O is 376 lb-ft counterclockwise.
6 0
2 months ago
A window washer on a hanging platform cleans the outside of windows on a skyscraper. The washer hoists the platform up the side
kicyunya [3294]

Answer:

The acceleration of the platform is - 1.8 m/s²

Explanation:

The net force on a body causes that body to accelerate in the direction of the resultant force applied.

Setting up the force equilibrium for the configuration:

ma = 800 - mg

100a = 800 - 100×9.8

100a = - 180

100a = - 180

a = - 1.8 m/s²

This indicates that the body is falling downward.

6 0
3 months ago
Other questions:
  • A 2.50-kg textbook is forced against a horizontal spring of negligible mass and force constant 250 N/m, compressing the spring a
    10·1 answer
  • A marble rolls with a velocity of 10 mm/s [E] on a game board that is being pulled [60o N of E] at 40.0 mm/s. What is the veloci
    10·1 answer
  • You ride a roller coaster with a loop-the-loop. Compare the normal force that the seat exerts on you to the force that Earth exe
    14·1 answer
  • A steel plate shine but wooden vessel desnt
    15·3 answers
  • You are exploring a planet and drop a small rock from the edge of a cliff. In coordinates where the +y direction is downward and
    5·1 answer
  • A worker pushes a 7 kg shipping box along a roller track. Assume friction is small enough to be ignored because of the rollers.
    10·1 answer
  • The chart shows rate of decay. A 3 column table with 7 rows. The first column is Half-lives elapsed, with entries 0, 1, 2, 3, 4,
    9·2 answers
  • A 817 kg car has four 8.91 kg wheels. When the car is moving, what fraction of the total kinetic energy of the car is due to rot
    12·1 answer
  • Max and Jimmy want to jump on a trampoline. Max begins jumping in a steady pattern, making small waves in the trampoline. Jimmy
    6·1 answer
  • A 8.00g sample of substance (substance, molar mass = 152.0 g/mol) was combusted in a bomb calorimeter with a heat capacity of 6.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!