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lisabon 2012
1 month ago
13

To practice Problem-Solving Strategy 10.1 for energy conservation problems. A sled is being held at rest on a slope that makes a

n angle θ with the horizontal. After the sled is released, it slides a distance d1 down the slope and then covers the distance d2 along the horizontal terrain before stopping. Find the coefficient of kinetic friction μk between the sled and the ground, assuming that it is constant throughout the trip.
Physics
1 answer:
serg [3.5K]1 month ago
5 0
μk = (d1)sin(θ) / [(cosθ)(d1) + (d2)]. According to the work/energy theorem, the change in kinetic energy of an object is equal to the total work done by all forces on it. As the object starts and ends at rest, the change in kinetic energy is zero, which indicates that the cumulative work done must also equal zero.
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10. How far does a transverse pulse travel in 1.23 ms on a string with a density of 5.47 × 10−3 kg/m under tension of 47.8 ?????
serg [3582]

Answer: Tension = 47.8N, Δx = 11.5×10^{-6} m.

              Tension = 95.6N, Δx = 15.4×10^{-5} m

Explanation: The speed of a wave on a string under tension can be determined using the following:

|v| = \sqrt{\frac{F_{T}}{\mu} }

F_{T} denotes tension (N)

μ refers to linear density (kg/m)

Calculating the velocity:

|v| = \sqrt{\frac{47.8}{5.47.10^{-3}} }

|v| = \sqrt{0.00874 }

|v| = 0.0935 m/s

Distance a pulse traveled in 1.23ms:

\Delta x = |v|.t

\Delta x = 9.35.10^{-2}*1.23.10^{-3}

Δx = 11.5×10^{-6}

With a tension of 47.8N, the distance a pulse will cover is Δx = 11.5×10^{-6}  m.

When tension is doubled:

|v| = \sqrt{\frac{2*47.8}{5.47.10^{-3}} }

|v| = \sqrt{2.0.00874 }

|v| = \sqrt{0.01568}

|v| = 0.1252 m/s

Distance in the same time:

\Delta x = |v|.t

\Delta x = 12.52.10^{-2}*1.23.10^{-3}

\Delta x = 15.4×10^{-5}

With the increased tension, it moves \Delta x = 15.4×10^{-5} m

4 0
2 months ago
Suppose you are designing an amplifier and loudspeaker system to use at a rock concert. You want to make it as loud as possible.
Softa [3030]
The response is outlined below. Audio power amplifiers are present in various sound systems, including those for sound reinforcement, public addresses, home audio, and musical instrument amplifiers like those for guitars. This component is the final electronic element in the audio playback chain before signals reach the loudspeaker. To achieve the loudest possible sound, it is essential to maximize output while maintaining high input and low output impedance.
4 0
1 month ago
A small sphere of radius R is arranged to pulsate so that its radius varies in simple harmonic motion between a minimum of R−x a
Softa [3030]
The sound wave intensity at the sphere's surface is described as follows: B = Bulk modulus. The oscillation amplitude of the sphere can be represented as: Substitute velocity and amplitude into Pmax. The intensity of the sound wave at a distance is determined by:
5 0
1 month ago
a professional baseball player can pitch a baseball with a velocity of 44.7m/s towards home plate. If a baseball weighs 1.4 N, h
Sav [3153]
To find the mass using a weight of 1.4 N:
1.4/9.8 = 0.1428 kg
The momentum is calculated as 0.1428 multiplied by 44.7, which is 6.38 kgm/s.
3 0
2 months ago
Read 2 more answers
Consider a bicycle wheel to be a ring of radius 30 cm and mass 1.5 kg. Neglect the mass of the axle and sprocket. If a force of
inna [3103]

To address the issue, it is essential to utilize the equations of Torque along with their definitions.

Torque is described as,

\tau = I \alpha

where,

I=Moment of Inertia

\alpha = Angular acceleration

Additionally, Torque in relation to linear motion is indicated as,

\tau = F*d

with,

F = Force

d= distance

The provided parameters are as follows:

R = 30 cm = 0.3m

m = 1.5 kg

F = 20 N

r = 4.0 cm = 0.04 m

t = 4.0s

Thus, aligning the two equations, we find that:

d*F = I\alpha

For a wheel, the moment of inertia is expressed as,

I= mR², substituting yields

d*F= \frac{mR^2a}{R}

d*F= mRa

a = \frac{rF}{ mR}

a = \frac{0.04*20}{1.5*0.3}

a=1.77 m/s^2

Therefore, the wheel's velocity is

V = a *t \\V=1.77*4 \\V=7.11 m/s

Consequently, the right answer is D.

4 0
1 month ago
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