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ArbitrLikvidat
22 days ago
9

How to write 12430000 in expanded form

Mathematics
2 answers:
tester [11.9K]22 days ago
8 0
10,000,000 + 2,000,000 + 400,000 + 30,000
PIT_PIT [11.9K]22 days ago
5 0
10000000 + 2000000 + 400000 + 30000
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When Joanne checked her Work by substituting the value of the variable back into the equation she got an answer of 12.34 equals
babunello [11366]

Answer:

Joanne might have utilized a rounded figure at a specific decimal point instead of the precise value. When validating her solution with a rounded figure, the outcome may not align precisely. The values, 12.34 and 12.33, are very similar, allowing Joanne to conclude that she correctly solved the multistep equation.

Step-by-step explanation:

Facts

3 0
1 month ago
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Student researchers Haley, Jeff, and Nathan saw an article on the Internet claiming that the average vertical jump for teens was
tester [11961]

Answer:

At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.

Step-by-step explanation:

A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.

The null and alternative hypotheses are:

H_0: \mu=15\\\\H_a: \mu\neq15

The significance level is set at 0.10.

The sample mean recorded is 17, and the sample standard deviation is 5.37.

The degrees of freedom are calculated as df=(20-1)=19.

The t-statistic is:

t_{19}=\frac{M-\mu}{s_M/\sqrt{n}} =\frac{17-15}{5.37/\sqrt{20}}=\frac{2}{5.37/4.47} =2/1.20=1.67

The two-tailed P-value corresponding to t=1.67 is P=0.11132.

<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.

At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.

7 0
1 month ago
How many possible values for y are there where y = cos^-1 0?
Zina [12044]

The potential values for y areinfinite

Further clarification

Trigonometry is a branch of math focused on the connections between the sides and angles of triangles.

Considering special angles of trigonometric functions, for instance

\displaystyle sin~0=0\\\\cos~30=\frac{1}{2}\sqrt{3}\\\\tan~45=1\\\\sec~45=\sqrt{2}\\\\etc.

In the equation y = cos⁻¹ 0, the value of y can be derived as follows:

y = cos⁻¹0

y = arc cos 0

cos y = 0

Thus, the resulting value of y:

\displaystyle \frac{\pi }{2},\frac{3}{2}\pi,\frac{5}{2}\pi, etc

Alternatively, it can be expressed as:

\displaystyle y=\frac{\pi }{2} (2n-1) ⇒ y: arithmetic sequence

So there are infinite solutions for y

Learn more

trigonometric identities

Keywords: trigonometric, infinite values,arithmetic sequence

3 0
20 days ago
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A father lifts a toddler 1.5 m up in the air. The child gains 187.5 J of energy in her gravitational potential energy store as a
Svet_ta [12380]

The toddler weighs 12.5 kg.

In-depth explanation:

The formula for gravitational potential energy is Ep=mgh where;

Ep=gravitational potential energy

m=mass of an object

g=gravitational field strength

h=height in meters

Given that; h= 1.5m, Ep=187.5J, g=10 N/kg then finding m;

Ep=mgh

187.5=m*10*1.5

187.5=15m

187.5/15 =15m/15

m=12.5 kg

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  • Gravitation potential energy:

Keywords: Mass, gravitational potential energy

5 0
19 days ago
In the diagram, DG = 15, GF = 5, EH = 12, and DE = 8. To prove that △DFE ~ △GFH by the SSS similarity theorem using the informat
lawyer [12163]

Answer: C) HF measures 4 units and GH is 2 units.

Step-by-step explanation:

The SSS similarity theorem asserts that triangles are similar if the lengths of their corresponding sides are in proportion.

For triangles ΔDFE and ΔGFH:

DG equals 15, GF is 5, EH equals 12, and DE is 8.

To demonstrate the similarity of ΔDFE and ΔGFH according to the SSS similarity theorem, we require:

\frac{DF}{GF}=\frac{FE}{FH}=\frac{DE}{GH}\\\\\Rightarrow\frac{DG+GF}{GF}=\frac{FH+EH}{FH}=\frac{DE}{GH}\\\\\Rightarrow\frac{5+15}{5}=\frac{12+HF}{FH}=\frac{8}{GH}\\\\\Rightarrow\frac{20}{5}=\frac{12+HF}{FH}\ and\ \frac{20}{5}=\frac{8}{GH}\\\\\Rightarrrow4HF=12+HF\ and\ GH=\frac{8}{4}\\\\\Rightarrow3HF=12\ and\ GH=2\\\\\Rightarrow HF=4\ and\ GH=2

Thus, to confirm that △DFE is similar to △GFH utilizing the SSS similarity theorem and the data from the diagram, it is essential to establish that HF measures 4 units and GH measures 2 units.

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29 days ago
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