During this phase, she traveled at <span>4 miles per hour (x*4)
and for the remainder of the distance (which is 0.7-x, since the total time was 42 minutes, thus the rest equates to 0.7-x), her speed was 5 miles per hour - therefore the distance covered was (0.7-x)*5 m/h
. The overall distance totaled 3 miles, so by combining both distances, we arrive at this equation:
x*4+ (0.7-x)*5=3
removing the brackets gives us:
4x+0.7*5-5x=3
</span>
<span>4x+3.5-5x=3
subtracting 3.5 from each side yields:
4x-5x=3-3.5
-x=-0.5
multiplying both sides by (-1)
x=0.5:
therefore, she walked for half an hour by herself, which amounts to 30 minutes!</span>
Response:
.
Detailed explanation:
We have a set of equations provided. Our task is to find the solution for this system.
Starting from equation (2), we will derive:
Next, by inserting this value into equation (1), we will achieve:
After multiplying both sides by 3, we will arrive at:
Now substituting this back into equation (2), we will find:
Thus, the solution to our specified set of equations is .
Answer:
The four odd numbers in sequence are 89, 90, 91, and 93.
Step-by-step explanation:
Designate the four consecutive numbers as x, x+2, x+4, and x+6.
Based on the information given in the question
x + (x + 2) + (x + 4) + (x + 6) = 368
4x + 12 = 368
4x = 356
x = 89
Consequently, the numbers are 89, 90, 91, and 93.
Hope this is helpful:)
Answer:
A), B), and C) are clarified below.
Step-by-step explanation:
The inquiry involves using binary digits, employing probabilities that are equal for both conditions, by applying a random test pattern, where the formula is derived from p = q.
Simplifying gives us
P[k] = nCk / 2^n
A. Probability of all bits being 1s
16c16/2^16 = 1/65536
B. Probability of all bits being 0s
16c0/2^16 = 1/65536
C. The probability of having exactly 8 bits as 1s and the other 8 as 0s
16c8/2^16 = 12870/65536 => 0.1963 ≈ 19.63%
