Trans fats: Think about how the prefix trans- is used in naming alkenes.

Answer:

A Reaction

3. Pt(NO₃)₂(aq) + Cu(s)

4. Cr(s) + H₂SO₄(aq)

B Non Reaction

1. Mn(s) + Ca(NO₃)₂(aq)

2. KOH(aq) + Fe(s)

Y > Q > W > Z > X

Explanation:

The first task is determining if a reaction is set to take place according to the chemical equations outlined below.

1. Mn(s) + Ca(NO₃)₂(aq)

2. KOH(aq) + Fe(s)

3. Pt(NO₃)₂(aq) + Cu(s)

4. Cr(s) + H₂SO₄(aq)

Reactivity differs among elements; thus, they can be ordered by their reactivity levels.

1. Mn(s) + Ca(NO₃)₂(aq)

This reaction will not happen as Mn cannot replace Ca in its compound. A more reactive element typically displaces a less reactive one.

2. KOH(aq) + Fe(s)

The reaction is non-existent because Iron is less reactive compared to potassium, thus cannot replace it.

3. Pt(NO₃)₂(aq) + Cu(s)

Copper's reactivity exceeds that of platinum, allowing it to easily displace platinum. Therefore, this reaction will certainly occur.

4. Cr(s) + H₂SO₄(aq)

Chromium's position in the reactivity series is higher than that of hydrogen, enabling it to displace hydrogen in this compound. Consequently, this reaction will take place.

Based on the reactions

Q + W + Reaction occurs

Since a reaction occurs, element Q is more reactive, successfully displacing element W from the compound.

X + Z + No reaction

No reaction takes place since element X is less reactive than Z, and thus cannot displace Z.

W + Z + Reaction occurs

Here, element W is more reactive than Z, enabling it to displace Z from the compound.

Q + Y + Reaction occurs

In this instance, element Y is more reactive than Q, successfully displacing Q from its compound.

This results in the overall reactivity ranking as Y > Q > W > Z > X

The result is 324.3 grams. In this problem, we have 6.0 moles of nitrous acid and need to convert it into grams. This conversion requires multiplying the moles by the molar mass of the substance. Molar mass is computed from the formula mass, with atomic masses of each constituent atom multiplied by their subscripts. For instance, A single nitrogen atom and a single oxygen atom yield the molar mass of the formula calculated as: atomic mass of N + 2(atomic mass of O) = 14 + 2(16) = 14 + 32 = 46 gram per mol. This molar mass indicates that 1 mole of the compound weighs 46 grams. Now let’s compute the molar mass of nitrous acid similarly. Its molar mass would be 1 + 14 + 2(16) = 1 + 14 + 32 = 47 grams per mol. Subsequently, the grams equivalent of 6.9 moles of nitrous acid calculates to 324.3 g.

Answer:

189.2 KJ

Explanation:

Provided Data

light wavelength = 632.8 nm

Convert nm to meters

1 nm = 1 x 10⁻⁹

632.8 nm = 632.8 x 1 x 10⁻⁹ = 6.328 x 10⁻⁷m

What is the energy of 1 mole of photons?

Solution

Used Formula

                     E = hc/λ

where

E = energy per photon

h = Planck's Constant

Planck's Constant = 6.626 x 10⁻³⁴ Js

c = speed of light

speed of light = 3 × 10⁸ ms⁻¹

λ = wavelength of light

Insert values into the equation

                   E = hc/λ

                   E = 6.626 x 10⁻³⁴ Js ( 3 × 10⁸ ms⁻¹ / 6.328 x 10⁻⁷m)

                   E = 6.626 x 10⁻³⁴ Js (4.741 x 10¹⁴s⁻¹)

                  E = 3.141 x 10⁻¹⁹J

3.141 x 10⁻¹⁹J indicates the energy for a single photon

Next, we need to determine the energy for 1 mole of photons

It is known that

1 mole contains 6.022 x10²³ photons

Consequently,

     Energy for one mole of photons = 3.141 x 10⁻¹⁹J x  6.022 x10²³

     Energy for one mole of photons = 1.89 x 10⁵ J

Now convert J to KJ

1000 J = 1 KJ

1.89 x 10⁵ J = 1.89 x 10⁵ /1000 = 189.2 KJ

Thus,

the energy for one mole of photons is 189.2 KJ

This represents a double displacement reaction.

The correct answers are B and D. Explanation: Given the information presented, we have absorption bands at 3300 cm-1 and 2200 cm-1, indicating the presence of an alkyne functional group. Furthermore, the hydrogenation of the unknown compound utilizes two moles of hydrogen, which correlates with the two pi bonds found in the alkyne group. Hence, we can eliminate choices "a" and "e." Since hydrogenation yields 2-methylhexane, option c is also dismissed, given that the methyl group attaches at carbon 3. Therefore, structures b and d remain viable.