1 point There are 118 known elements. How many elements have atoms, in their ground-state, with core electrons whose quantum num

Answer: The molecular formula will be

Explanation:

When percentages are provided, we assume the total mass to be 100 grams.

Thus, the mass of each element corresponds to the specified percentage.

Mass of C= 70.6 g

Mass of H = 5.9 g

Mass of O = 23.5 g

Step 1: convert given masses to moles.

Moles of C =

Moles of H =

Moles of O =

Step 2: For determining the mole ratio, divide each molar amount by the smallest number of moles calculated.

For C =

For H =

For O =

The resulting ratio of C: H: O= 4: 4: 1

Hence, the empirical formula obtained is

The empirical weight is calculated as = 4(12)+4(1)+1(16)= 68g.

The molecular weight = 136 g/mole

Now the molecular formula needs to be obtained.

The molecular formula can be derived as=

This appears to be an essay question based on an experiment. Different oxidizing agents possess varying strengths. When compared to nitric acid (HNO3), sulfuric acid (H2SO4) serves as a weaker oxidizing agent. Therefore, using H2SO4 in place of HNO3 would not yield the same experimental results.

Answer:

THE MOLAR MASS OF XCL2 IS 400 g/mol

THE MOLAR MASS OF YCL2 IS 250 g/mol.

Explanation:

We derive the molar mass of XCl2 and YCl2 by recalling the molar mass formula when both mass and the number of moles are known.

Number of moles = mass / molar mass

Molar mass = mass / number of moles.

For XCl2,

mass = 100 g

number of moles = 0.25 mol

Thus, molar mass = mass / number of moles

Molar mass = 100 g / 0.25 mol

Molar mass = 400 g/mol.

For YCl2,

mass = 125 g

number of moles = 0.50 mol

Molar mass = 125 g / 0.50 mol

Molar mass = 250 g/mol.

Accordingly, the molar masses for XCl2 and YCl2 are 400 g/mol and 250 g/mol, respectively.

Answer:

78.96 g of NaC2H3O2

Explanation:

The following information is provided:

• The solution's volume is 350 mL
• The solution's molarity is 2.75 M
• The molar mass of NaC2H3O2 is 82.04 g/mol

We need to find the mass of the solute:

First, we calculate the number of moles:

Moles = Molarity × Volume

Thus;

Moles of solute = 2.75 M × 0.350 L

                        = 0.9625 moles

Next, we find the mass:

Mass = Moles × Molar mass

        = 0.9625 moles × 82.04 g/mol

        = 78.9635 g

      = 78.96 g

Therefore, the amount of NaC2H3O2 required is 78.96 g

To start, consult the periodic table to pinpoint the element with an average atomic mass of 24.3. The amu is simply the number listed under the element, leading us to conclude that Mg is the answer.