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1 month ago

BHE:FLI:JPM next sequence

Engineering

1 answer:

grin007 [323]1 month ago

0 0

Answer:

NTQ

Explanation:

The sequence provided is

BHE : FLI : JPM

It is evident that the initial letters are B, F, and J. The gap between their positions in the alphabet is 4.

B+4=F, F+4=J; hence, the first letter of the subsequent term is J+4=N.

For the second letters, we have H, L, P. Their positional difference also amounts to 4.

H+4=L, L+4=P; thus, the second letter of the upcoming term will be P+4=T.

The third letters are E, I, M. Likewise, their positional difference is 4.

E+4=I, I+4=M; therefore, the third letter of the next term is M+4=Q.

Consequently, the next term is NTQ.

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You want to determine whether the race of the defendant has an impact on jury verdicts. You assign participants to watch a trial

grin007 [323]

Response:

The confidence scale is an ordinal measurement scale

Clarification:

An ordinal measurement scale is utilized for assessing attributes that can be ranked or ordered, yet the intervals in between attributes lack quantitative meaning. In this scenario, the scale utilized was from 1 to 7, where "1" signifies that the defendant's race has little impact on jury verdicts, and "7" indicates a strong impact of race on such verdicts. For instance, in a survey measuring customer satisfaction for a product, a "1" indicates great dissatisfaction, while "10 " denotes highest satisfaction. In the first instance, it would be incorrect to assert that the difference between a rating of 1, which implies "not at all," and perhaps a 3, is equivalent to the gap between a 5 and a 7, as these numbers merely serve as labels devoid of quantifiable value.

Other types of measurement levels include:

1. Nominal: This is the most straightforward measurement level, employed primarily for categorizing attributes. An example would be gathering data on gender, with categories such as male, female, and transgender.

2. Interval: An interval scale is used when the distances between two attributes hold meaning, but a true zero point is absent from the scale.

3. Ratio: This level combines all three previously mentioned measurements, serving to categorize, show ranking, maintain meaningful distances between attributes, and possess a true zero point. A typical example is measuring temperature using a Celsius thermometer, which has a true zero at 0°C, and the intervals between 5°C and 10°C are equivalent to those between 10°C and 15°C.

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21 day ago

Steam flows at steady state through a converging, insulated nozzle, 25 cm long and with an inlet diameter of 5 cm. At the nozzle

iogann1982 [368]

Answer:

The velocity at exit U_2 is 578.359 m/s

The exit diameter d_e is 1.4924 cm

Explanation:

Provided data includes:

Length of the nozzle L = 25 cm

Inlet diameter d_i = 5 cm

At the nozzle entrance (state 1): Temperature T_1 = 325 °C, Pressure P_1 = 700 kPa, Velocity U_1 = 30 m/s, Enthalpy H_1 = 3112.5 kJ/kg, Volume V_1 = 388.61 cm³/gAt the nozzle exit (state 2): Temperature T_2 = 250 °C, Pressure P_2 = 350 kPa, Velocity U_2, Enthalpy H_2 = 2945.7 kJ/kg, Volume V_2 = 667.75 cm³/g To determine:a. Exit Velocity U_2b. Exit Diameter d_e

a.The Energy Equation can be represented by:ΔH + ΔU² / 2 + gΔz = Q + WAssuming Q = W = Δz = 0Substituting the values yields:

(H_2 - H_1) + (U²_2 - U²_1) / 2 = 0From which we can derive U_2 = sqrt((2* (H_1 - H_2 )) + U²_1) with the calculations leading to U_2 = sqrt ( 2 * 10^3 * (3112.5 -2945.7) + 900) yielding U_2 = 578.359 m/s

Using mass balance approach, we have U_1 * A_1 / V_1 = U_2 * A_2 / V_2

Here, A = π*d² / 4

This leads to U_1 * d_i² / V_1 = U_2 * d_e² / V_2, thus d_e = d_i * sqrt((U_1 / U_2) * (V_2 / V_1)). Hence, d_e = 5 * sqrt((30 / 578.359) * (667.75 / 388.61)) computes to d_e = 1.4924 cm

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21 day ago

A hydrogen-filled balloon to be used in high altitude atmosphere studies will eventually be 100 ft in diameter. At 150,000 ft, t

mote1985 [299]

Answer:

The calculated result is 11.7 ft

Explanation:

You can apply the combined gas law, which incorporates Boyle's law, Charles's law, and Gay-Lussac's Law, because hydrogen demonstrates ideal gas behavior under these specific conditions.

$\frac{p_1 V_1}{T_1} = \frac{p_2 V_2}{T_2}$

where the subscripts indicate "p" for pressure, "V" for volume, and "T" for temperature (in Kelvin) at varying moments. Let's denote $t_1$ as the balloon at 150,000 ft so

$p_1 = 0.14 \ lb/in^2$

$V_1 = \frac{4}{3} \pi R_1^3 = 523598.77 \ ft^3$

and $T_1 = -67^\circ F = 218.15\ K$ .

Then $t_2$ represents the point at which the balloon is on the ground.

$p_2 = 14.7 \ lb/in^2$ and $T_2 = 68^\circ F = 293.15\ K$ .

Based on the first equation

$V_2 = \frac{p_1 V_1 T_2}{T_1 p_2}$ , we find

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$R_2 = \sqrt[3]{\frac{3 V_2}{4 \pi}} = 11.7 \ ft$ .

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21 day ago

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choli [298]

Answer:

Flame-resistant clothing and aprons

Explanation:

Workers involved with welding are generally mandated to wear flame-resistant clothing and aprons to shield them from various hazards, including heat, flames, burns, and potential radiation. In the context of welding, this gear protects individuals from flying sparks that can ignite and cause fires. Hence, such clothing helps to prevent accidents in these situations.

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1 month ago

Helium gas is compressed from 90 kPa and 30oC to 450 kPa in a reversible, adiabatic process. Determine the final temperature and

choli [298]

Answer:

T2 ( final temperature ) = 576.9 K

a) 853.4 kJ/kg

b) 1422.3 kJ / kg

Explanation:

given data:

pressure ( P1 ) = 90 kPa

Temperature ( T1 ) = 30°c + 273 = 303 k