<span>Conclusion: The door's weight results in a CCW torque which can be calculated as
Tccw = 145 N*3.13 m / 2.
You require a CW torque that balances this
Tcw = F*2.5 m*sin20</span>
To start, we first need to determine the kinetic energy of the penny before it strikes the ground. This is calculated using the formula where m equals 5.25 g, which is 0.00525 kg for the penny's mass, and v equals 3.27 m/s for its speed. Replacing the values into the equation provides: When the penny lands, all this kinetic energy transforms into internal energy for both the penny and the ground. If half of this energy goes into the penny's internal energy, the change is determined by a specific formula where m is the penny's mass, Cs is its specific heat capacity (2.03 J/gC), and
, the change in temperature. To find the last element, the equation will be solved.
Answer:
A. 2.57 K
Explanation:
Using the specific heat capacity,
Q = cmΔT........................ Equation 1
Where Q = Heat energy absorbed by silver, m = mass of silver, c = specific heat capacity for silver, ΔT = temperature change of the silver.
Rearranging gives ΔT as the subject of the equation
ΔT = Q/cm................... Equation 2
Provided: Q = 300 J, m = 500 g = 0.5 kg
Constant: c = 233 J/kg.K
Inserting values into equation 2 yields
ΔT = 300/(0.5×233)
ΔT = 300/116.5
ΔT = 2.57 K
Therefore, the correct answer is A. 2.57 K
Answer: c. 4.56 × 105 J
Explanation:
Given the mass of the lead brick, m = 7.25 kg
Starting temperature T1 = 18.0 °C
Ending temperature T2 = 328 °C
The specific heat capacity for lead, c = 128 J/(kg∙°C)
And the latent heat of fusion Lfusion = 23,200 J/kg
The required energy Q =?
Using the following equations
Energy required, Q = mc (T2 - T1) + mLfusion
Substituting in the values we have: 7.25 kg * 128 J/(kg∙°C) * (328 - 18°C) + 7.25 kg * 23200 J/kg
= 455880 J
= 4.56 x 10^5 J
The structure with the least oxygen is the vena cava. I hope this information is useful!
