answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kolbaska11
1 month ago
8

The following five beakers, each containing a solution of sodium chloride (NaCl, also known as table salt), were found on a lab

shelf:
Beaker Contents
1) 200. mL of 1.50 M NaCl solution
2) 100. mL of 3.00 M NaCl solution
3) 150. mL of solution containing 19.5 g of NaCl
4) 100. mL of solution containing 19.5 g of NaCl
5) 300. mL of solution containing 0.450 mol NaCl

Arrange the solutions in order of decreasing concentration.
Chemistry
2 answers:
lions [2.9K]1 month ago
7 0

Answer:

The order of the solutions based on decreasing concentration:

(IV) > (II) > (III) > (I)  = (V)

Explanation:

1) 200 mL of 1.50 M NaCl solution  - (I)

Given concentration of NaCl is [NaCl]= 1.50 M

2) 100 mL of 3.00 M NaCl solution  - (II)

Given concentration of NaCl is [NaCl]= 3.00 M

3) 150 mL solution with 19.5 g of NaCl  - (III)

Calculated moles of NaCl = \frac{19.5 g}{58.5 g/mol}= 0.3333 mol

Volume of solution is 150 mL = 0.150 (1L = 1000 mL)

[NaCl]=\frac{0.3333 mol}{0.150 L}=2.222 M

4) 100 mL solution containing 19.5 g of NaCl  - (IV)

Calculated moles of NaCl = \frac{19.5 g}{58.5 g/mol}= 0.3333 mol

Volume of solution is 100 mL = 0.100 (1L = 1000 mL)

[NaCl]=\frac{0.3333 mol}{0.100 L}=3.333 M

5) 300 mL of solution with 0.450 mol NaCl - (V)

Calculated moles of NaCl = 0.450 mol

Volume of solution is 300 mL = 0.300 (1L = 1000 mL)

[NaCl]=\frac{0.450 mol}{0.300 L}=1.50 M

The order of the solutions based on decreasing concentration:

(IV) > (II) > (III) > (I)  = (V)

Anarel [2.9K]1 month ago
4 0

Answer:

Please review the following responses

Explanation:

1) A solution of 100. mL contains 19.5 g of NaCl  (3.3M)

2) 100. mL of NaCl solution at 3.00 M (3 M)

3) A solution of 150. mL holds 19.5 g of NaCl  (2.2 M)

4) The concentrations of beakers 1 and 5 are identical (1.5M)

Molar mass of NaCl = 23 + 36 = 59 g

For beaker number 3:

          59 g -------------- 1 mol

           19.5 g -------------   x

  x = 19.5 x 1/59 = 0.33 mol

Molarity (M) = 0.33 mol/0.150 l = 2.2 M

For beaker number 4:

Molarity (M) = 0.33mol/0.10 l = 3.3 M

For beaker number 5:

Molarity (M) = 0.450/0.3 = 1.5 M

You might be interested in
Compounds A and B are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 g of sulf
lorasvet [2795]

Answer:

1.5

Explanation:

It is given that:

Compound A and B originate from Sulfur + Oxygen.

Compound A:

6g sulfur + 5.99g Oxygen

Compound B:

8.6g sulfur + 12.88g oxygen

By comparing the ratios:

Compound A:

S: O = 6.00: 5.99

S/0 = 6.0g S / 5.99g O

Compound B:

S: O = 8.60: 12.88

S / O = 8.60g S / 12.88g O

The mass ratio of A and that of B

(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)

(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)

(6 × 12.88) / (5.99 × 8.60)

= 77.28 / 51.514

= 1.50017

= 1.5

4 0
27 days ago
When 1.34 g Zn(s) reacts with 60.0 mL of 0.750 M HCl(aq), 3.14 kJ of heat are produced. Determine the enthalpy change per mole o
Alekssandra [3086]

Answer: The change in enthalpy for each mole of zinc involved in the reaction is 152.4 kJ/mol.

Explanation:

First, we need to determine the moles of Zn and HCl.

\text{Moles of }Zn=\frac{\text{Mass of }Zn}{\text{Molar mass of }Zn}

The molar mass of Zn is 65 g/mole

\text{Moles of }Zn=\frac{1.34g}{65g/mole}=0.0206mole

and,

\text{Moles of }HCl=\text{Concentration of }HCl\times \text{Volume of solution}=0.750M\times 0.0600=0.0450mole

Next, we must identify the limiting reagent and the excess reagent.

The chemical reaction given is:

Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

According to the balanced reaction we find that

1 mole of Zn reacts with 2 moles of HCl

Thus, 0.0206 moles of Zn react with 0.0206\times 2=0.0412 moles of HCl

This leads us to determine that HCl is the excess reagent because the moles provided exceed the required moles, while Zn is limiting and restricts product formation.

Now to find the enthalpy change for each mole of zinc reacting in this reaction.

From the reaction we gather that,[ [TAG_59]]

0.0206 moles of Zn yield heat = 3.14 kJ

This implies that 1 mole of Zn generates heat = \frac{3.14kJ}{0.0206mol}=152.4kJ/mol

Hence, the enthalpy change per mole of zinc involved in this reaction amounts to 152.4 kJ/mol.

5 0
1 month ago
Compound A and Compound B are binary compounds containing only elements X and Y. Compound A contains 1.000 g of X for every 2.10
alisha [2963]
For 1.000 g of X, the mass of Y is 0.1621 g. The mass ratio of Y = 2.100 g: 0.1621 g equals 1:0.07. For 1.000 g of X, the mass of Y is 0.7391 g, which leads to a mass ratio of Y = 2.100 g: 0.7391 g simplifying to 1:0.35 or 20:7. For 1.000 g of X, the corresponding mass of Y is 0.2579 g, yielding a mass ratio of Y = 2.100 g: 0.2579 g resulting in 1:0.12. For 1.000 g of X, the mass of Y becomes 0.2376 g, giving a mass ratio of Y = 2.100 g: 0.2376 g, simplifying to 1:0.11. Lastly, for 1.000 g of X, the mass of Y is determined to be 0.2733 g, leading to a mass ratio of Y = 2.100 g: 0.2733 g which reduces to 1:0.13. Among the calculated values, option B aligns most closely with the law of multiple proportions.
7 0
14 days ago
Read 2 more answers
Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. G
Anarel [2989]
1) The chemical equation is

Cu + 2AgNO3 ---> Cu (NO3)2 + 2Ag

2) Molar ratios are as follows:

1 mol Cu: 2 moles AgNO3: 1 mol Cu (NO3)2: 2 mol Ag

3) Converting 12.83 * 10^23 atoms of Cu to moles gives:

12.83 * 10^23 atoms / (6.02 * 10^23 atoms / mol) = 2.131 mol Cu

4) Using the ratios:

2.131 mol Cu * 2 mol Ag / 1 mol Cu = 4.262 mol Ag

5) To convert 4.262 mol of silver to grams, use the atomic weight of silver:

mass = moles × atomic mass = 4.262 mol * 107.9 g / mol = 459.9 grams

Answer: 459.9 g
5 0
1 month ago
Select the atoms or ions drawn with valid Lewis dot structures. A) A carbon has a dot on top, right, bottom and to the left.a ni
KiRa [2933]
Answer:

B, C

Explanation:

The Lewis dot structures that are valid are for B and C.

Regarding A;

The Lewis representation of carbon is correct. Each of the four dots symbolizes the four valence electrons.

However, the nitrogen with a single dot above, to the left, and below and a -3 charge isincorrect. For it to have a -3 charge, it must possess 8 Lewis dots (two on each side).

The nitrogen showing four dots (on top, right, bottom and left) is incorrect.

In B;

An oxygen having two dots positioned above and below with one dot on both sides is correct , as the 6 dots indicate oxygen's valence electrons.

In C;

A carbon shows two dots at each position and has a charge of +4. This is correct because the charge reflects that it has gained four electrons giving it 8 valence electrons.

In D;

An oxygen shows two dots above, to the left and below, with a charge of -2. This is incorrect as not all Lewis dots are present. Two are missing.

6 0
1 month ago
Other questions:
  • Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca2+, V5+, Br-
    13·1 answer
  • How many carbon atoms are there in a 1.3-carat diamond? diamonds are a form of pure carbon. (1 carat?
    13·2 answers
  • When 200g of AgNO3 solution mixes with 150 g of NaI solution, 2.93 g of AgI precipitates, and the temperature of the solution ri
    13·1 answer
  • How many liters of gas will be in the closed reaction flask when 36.0L of ethane (C2H6) is allowed to react with 105.0L of oxyge
    6·1 answer
  • Calculate the value of E°cell for the following reaction:2Au(s) + 3Ca2+(aq) → 2Au3+(aq) + 3Ca(s)Au3+(aq) + 3e- → Au(s) E° = 1.50
    14·1 answer
  • If 7.50 g of the unknown compound contained 0.250 mol of c and 0.500 mol of h, how many moles of oxygen, o, were in the sample?
    14·1 answer
  • How much pressure would 0.8 moles of a gas at 370K exert if it occupied 17.3L of space
    12·2 answers
  • what does the number of the places after the decimal in a measurement tell you about the precision of the instrument that record
    8·1 answer
  • A carbene is a highly reactive intermediate in which a carbon atom bears a lone pair and no formal charge: how many hydrogen ato
    9·1 answer
  • If the original sample of Zn had a mass of 1.4 g, what mass of ZnCl2 can be produced in the reaction?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!