A coil of 1000 turns of wire has a radius of 12 cm and carries a counterclockwise current of 15A. If it is lying flat on the gro
1 answer:
Answer:
the torque is calculated to be 1.7 * Nm
Explanation:
Provided information
Number of turns n = 1000
radius r = 12 cm
current I = 15A
magnetic field magnitude B = 5.8 x 10^-5 T
angle θ = 25°
to calculate
the torque on the loop
solution
the formula for torque on the loop is given by
torque = N* I* A*B* sinθ
where area A = πr² = π(0.12)²
substituting the values
torque = N* I* A*B* sinθ
torque = 1000* 15* π(0.12)² *5.8 x 10-5 * sin(25)
torque = 0.0166 N m
the torque is found to be 1.7 * Nm
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