A coil of 1000 turns of wire has a radius of 12 cm and carries a counterclockwise current of 15A. If it is lying flat on the gro

Question

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A coil of 1000 turns of wire has a radius of 12 cm and carries a counterclockwise current of 15A. If it is lying flat on the gro

und, and the Earth's magnetic field points due north, has a magnitude of 5.8 x 10-5 T, and makes a downward angle of 25Â° with the vertical, what is the torque on the loop?

Physics

1 answer:

ValentinkaMS [3.4K] · Answer 1 · 2026-03-14T08:02:36+03:00

Answer:

the torque is calculated to be 1.7 * $10^{-2}$ Nm

Explanation:

Provided information

Number of turns n = 1000

radius r = 12 cm

current I = 15A

magnetic field magnitude B = 5.8 x 10^-5 T

angle θ = 25°

to calculate

the torque on the loop

solution

the formula for torque on the loop is given by

torque = N* I* A*B* sinθ

where area A = πr² = π(0.12)²

substituting the values

torque = N* I* A*B* sinθ

torque = 1000* 15* π(0.12)² *5.8 x 10-5 * sin(25)

torque = 0.0166 N m

the torque is found to be 1.7 * $10^{-2}$ Nm