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Nuetrik
3 months ago
10

A person applies an impulse of 5.0 kg∙m/s to a box in order to set it in motion. If the person is in contact with the box for 0.

25 s, what is the average force exerted by the person on the box?
Physics
1 answer:
Keith_Richards [3.2K]3 months ago
0 0

Answer:

F = 20 N

Explanation:

Given,

Impulse, I = 5 Kg.m/s

Contact duration, t = 0.25 s

Average force = ?

It is known that force equals the change in momentum over time.

Impulse is equivalent to the change in momentum.

F = \dfrac{dP}{dt}

F = \dfrac{I}{t}

F = \dfrac{5}{0.25}

F = 20 N

The average force applied by the individual on the box is F = 20 N

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