Answer:
v = [√(g/2h)]L
Explanation:
Let v represent the initial horizontal speed, and t denote the duration James Bond takes to leap off the ledge of length, L.
Thus, we derive vt = L, which leads to t = L/v
Additionally, considering that Bond begins with no horizontal velocity, he descends freely over the height, h; thus the equation y - y' = ut - 1/2gt² is applicable, where y = 0 (top of the cliff) and y' = -h, u = 0 (initial vertical speed), g = acceleration due to gravity = 9.8 m/s², and t = the time required to leap from the cliff = L/v.
By substituting these parameters into the equation, we obtain
y' - y = ut - 1/2gt²
-h - 0 = 0 × t - 1/2g(L/v)²
-h = - 1/2gL²/v²
v² = gL²/2h
taking the square root of both sides gives us
v = [√(g/2h)]L
Therefore, James Bond's required minimum horizontal velocity is v = [√(g/2h)]L
Answer:
The density comes out to be 
Mg/µL
Explanation:
Given data:
The density of nuclear matter is approximately 
kg/m³
1 ml corresponds to 1 cm³
To determine:
The density of nuclear matter in Mg/µL
Solution:
We recognize that:
1 Mg equals 1000 kg
Thus, 1 m³ is equal to cm³
Moreover, 1 cm³ is equivalent to 1 mL
Thus, we can conclude that 1 mL is equal to 10³ µL
With this, we convert the density as follows:
Density = kg/m³
Density = kg/m³ × 
Mg/µL
Density = Mg/µL
Learning is essential as it enables individuals to gather the skills necessary for achieving their objectives. Additionally, it serves as a method for enhancing knowledge and acquiring abilities that will aid in attaining specific targets.
The result will be 21.6, but rounding yields 22J.
Starting speed of the coin (u)= 0 (Since it starts from rest)
Gravitational acceleration (a) = g = 9.81 m/s²
Duration of the fall (t) = 1.5 s
According to the motion equation we can state:
Substituting the known values into the equation yields:
v = 0 + 9.81 × 1.5
v = 14.715 m/s
The speed of the coin upon reaching the ground/Final speed of the coin = 14.715 m/s
