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lisov135
1 month ago
7

Mickey, a daredevil mouse of mass m , m, is attempting to become the world's first "mouse cannonball." He is loaded into a sprin

g-powered gun pointing up at some angle, and is shot into the air. The gun's spring has force constant k k and is initially compressed a distance X X from its relaxed position. If Mickey has a constant horizontal speed V V while he is flying through the air, how high above his initial location in the gun does Mickey soar? Find an expression for Mickey's maximum height h m hm in terms of m , m, V , V, X , X, k , k, and g .
Physics
2 answers:
Ostrovityanka [3.2K]1 month ago
8 0
The equations are h = v₀² / 2g, and h = k/4g x².
Softa [3K]1 month ago
6 0
h = v₀² / 2g, and h = k/4g x².
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Suppose you are drinking root beer from a conical paper cup. The cup has a diameter of 10 centimeters and a depth of 13 centimet
ValentinkaMS [3465]

Answer:

The rate at which the root beer level is decreasing is 0.08603 cm/s.

Explanation:

The formula for the volume of the cone is:

V=\frac {1}{3}\times \pi\times r^2\times h

Where V denotes the cone's volume

r indicates the radius

h signifies the height

The ratio of radius to height remains consistent throughout the cone.

Thus, we have r = d / 2 = 10 / 2 cm = 5 cm

h is 13 cm

Consequently, r / h = 5 / 13

r = {5 / 13} h

V=\frac {1}{3}\times \frac {22}{7}\times ({{{\frac {5}{13}\times h}}})^2\times h

V=\frac {550}{3549}\times h^3

Additionally, we differentiate the volume expression in relation to time:

\frac {dV}{dt}=\frac {550}{3549}\times 3\times h^2\times \frac {dh}{dt}

Given that \frac {dV}{dt} = -4 cm³/sec (the negative sign indicates outflow)

h equals 10 cm

Hence,

-4=\frac{550}{3549}\times 3\times {10}^2\times \frac {dh}{dt}

\frac{55000}{1183}\times \frac {dh}{dt}=-4

\frac {dh}{dt}=-0.08603\ cm/s

The rate at which the root beer level is decreasing is 0.08603 cm/s.

3 0
2 months ago
Using evidence from the article, defend the concept that Earth’s magnetic poles have swapped places over time.
Maru [3345]

Answer: Research has revealed signs of the Earth's magnetic field flipping in ocean floor rocks, especially at tectonic plate boundaries. These rocks exhibit alternating polarity because of the magnetization that happened as they solidified. Through radio metric dating, scientists suggest these reversals take place roughly every few hundred thousand years.

Explanation:

6 0
1 month ago
Suppose that a charged particle of diameter 1.00 micrometer moves with constant speed in an electric field of magnitude 1.00×105
Ostrovityanka [3204]
This is somewhat misleading, and I encountered the same question in my homework. An electric field strength of 1*10^5 N/C is provided, along with a drag force of 7.25*10^-11 N, and the critical detail is that it maintains a constant velocity, indicating that the particle is in equilibrium and not accelerating.
<span>To solve, utilize F=(K*Q1*Q2)/r^2 </span>
<span>You'll want to equate F with the drag force, where the electric field strength translates to (K*Q2)/r^2; substituting the values results in </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
3 0
1 month ago
Read 2 more answers
A cylinder has 500 cm3 of water. After a mass of 100 grams of sand is poured into the cylinder and all air bubbles are removed b
Keith_Richards [3271]

Answer: SG = 2.67

The specific gravity for the sand is 2.67

Explanation:

Specific gravity is determined by the formula: density of the substance/density of water

Provided information;

Mass of sand m = 100g

The volume of sand equals the volume of water it displaces

Vs = 537.5cm^3 - 500 cm^3

Vs = 37.5cm^3

Calculating density of sand = m/Vs = 100g/37.5 cm^3

Ds = 2.67g/cm^3

Density of water Dw = 1.00 g/cm^3

Thus, the specific gravity of the sand can be expressed as

SG = Ds/Dw

SG = (2.67g/cm^3)/(1.00g/cm^3)

SG = 2.67

The specific gravity of the sand stands at 2.67

3 0
1 month ago
An object is moving in the plane according to these parametric equations:
Maru [3345]
A. The horizontal component of velocity is
vx = dx/dt = π - 4πsin(4πt + π/2)
vx = π - 4πsin(0 + π/2)
vx = π - 4π(1)
vx = -3π

b. vy = 4πcos(4πt + π/2)
vy = 0

c. m = sin(4πt + π/2) / [πt + cos(4πt + π/2)]

d. m = sin(4π/6 + π/2) / [π/6 + cos(4π/6 + π/2)]

e. t = -1.0

f. t = -0.35

g. To find t, set
vx = π - 4πsin(4πt + π/2) = 0
Then use this to calculate vxmax

h. To determine t, set
vy = 4πcos(4πt + π/2) = 0
Then use this to find vymax

i. s(t) = [x(t)^2 + y(t)^2]^(1/2)

h. s'(t) = d[x(t)^2 + y(t)^2]^(1/2) / dt

k and l. Determine the values for t
d[x(t)^2 + y(t)^2]^(1/2) / dt = 0
And substitute to find both the maximum and minimum speeds.
5 0
2 months ago
Read 2 more answers
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