Answer:
The rate at which the root beer level is decreasing is 0.08603 cm/s.
Explanation:
The formula for the volume of the cone is:
Where V denotes the cone's volume
r indicates the radius
h signifies the height
The ratio of radius to height remains consistent throughout the cone.
Thus, we have r = d / 2 = 10 / 2 cm = 5 cm
h is 13 cm
Consequently, r / h = 5 / 13
r = {5 / 13} h
Additionally, we differentiate the volume expression in relation to time:
Given that 
= -4 cm³/sec (the negative sign indicates outflow)
h equals 10 cm
Hence,
The rate at which the root beer level is decreasing is 0.08603 cm/s.
Answer: Research has revealed signs of the Earth's magnetic field flipping in ocean floor rocks, especially at tectonic plate boundaries. These rocks exhibit alternating polarity because of the magnetization that happened as they solidified. Through radio metric dating, scientists suggest these reversals take place roughly every few hundred thousand years.
Explanation:
This is somewhat misleading, and I encountered the same question in my homework. An electric field strength of 1*10^5 N/C is provided, along with a drag force of 7.25*10^-11 N, and the critical detail is that it maintains a constant velocity, indicating that the particle is in equilibrium and not accelerating.
<span>To solve, utilize F=(K*Q1*Q2)/r^2 </span>
<span>You'll want to equate F with the drag force, where the electric field strength translates to (K*Q2)/r^2; substituting the values results in </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
Answer: SG = 2.67
The specific gravity for the sand is 2.67
Explanation:
Specific gravity is determined by the formula: density of the substance/density of water
Provided information;
Mass of sand m = 100g
The volume of sand equals the volume of water it displaces
Vs = 537.5cm^3 - 500 cm^3
Vs = 37.5cm^3
Calculating density of sand = m/Vs = 100g/37.5 cm^3
Ds = 2.67g/cm^3
Density of water Dw = 1.00 g/cm^3
Thus, the specific gravity of the sand can be expressed as
SG = Ds/Dw
SG = (2.67g/cm^3)/(1.00g/cm^3)
SG = 2.67
The specific gravity of the sand stands at 2.67
A. The horizontal component of velocity is
vx = dx/dt = π - 4πsin(4πt + π/2)
vx = π - 4πsin(0 + π/2)
vx = π - 4π(1)
vx = -3π
b. vy = 4πcos(4πt + π/2)
vy = 0
c. m = sin(4πt + π/2) / [πt + cos(4πt + π/2)]
d. m = sin(4π/6 + π/2) / [π/6 + cos(4π/6 + π/2)]
e. t = -1.0
f. t = -0.35
g. To find t, set
vx = π - 4πsin(4πt + π/2) = 0
Then use this to calculate vxmax
h. To determine t, set
vy = 4πcos(4πt + π/2) = 0
Then use this to find vymax
i. s(t) = [x(t)^2 + y(t)^2]^(1/2)
h. s'(t) = d[x(t)^2 + y(t)^2]^(1/2) / dt
k and l. Determine the values for t
d[x(t)^2 + y(t)^2]^(1/2) / dt = 0
And substitute to find both the maximum and minimum speeds.
