Response:
Tube 2: 8.26 * 10^-3; Tube 4: 6.83 * 10^-5
Explanation:
For the MIC test's serial dilutions, each tube should contain an equal volume of nutrient broth: 5.0 mL, while the agent's volume per dilution must also match: 0.5 mL.
The serial dilution process followed was:
- Tube 1: 0.5/5.5
- Tube 2: 0.5 mL from tube 1 was diluted with 5.0 mL of broth, resulting in a dilution of tube 2 as (1:11) * (1:11) = (0.5/5.5) * (0.5/5.5) = 1:121 = 8.26 * 10^-3
- Tube 3: similar calculations yield 1:1331 = 7.51 * 10^-4
- Tube 4: yields 1:14641 = 6.83 * 10^-5.
Answer:
The solution to your inquiry is C = 0.000333 kcal/g°C
or C = 0.333 cal/g°C
Explanation:
Data
Q = 1.67 kcal
mass = 79.2 g
ΔT = 63.3°C
Formula
Q = mCΔT
Solving for C
C = Q/mΔT
Substituting values
C = 1.67/(79.2 x 63.3)
Simplifying
C = 1.67 / 5013.4
Final Result
C = 0.000333 kcal/g°C
or C = 0.333 cal/g°C
Answer: second option: 1.70 to 1.40
Explanation:
1) pH is defined using the formula pH = - log [H₃O⁺]
2) Given that the initial concentration is x and after doubling it becomes 2x, we calculate:
pHi = - logx
pHf = - log 2x = - log 2 - logx
Thus, pHf - pHi = - log2 - logx - (- logx) = - log2 ≈ - 0.30
⇒ pHi - pHf = 0.30, indicating that the final pH (with twice the hydronium ions) is 0.30 lower than the starting pH.
3) The only option that indicates a 0.30 decline in pH is the second one: from 1.70 to 1.40. Therefore, that is the correct choice.
2C6H14 + 13O2 ---> 6CO2 +14H2O
Calculating the molar mass of C6H14: M(C6H14)=12.011*6 +1.008*14 ≈ 86.17 g/mol
Thus, 86.17 g of C6H14 corresponds to 1 mole.
2C6H14 + 13O2 ---> 6CO2 +14H2O
based on the equation 2 mol 6 mol
according to the question 1 mol 3 mol
To determine M(CO2): M(CO2)= 12.011 + 2*15.999= 44.009 g/mol
Therefore, 3 mol CO2*44.009 g/1 mol CO2 ≈ 132.0 g CO2
Final answer: 132.0 g CO2
Answer: The energies of infrared photons are comparable to those linked with various vibrational states of chemical bonds. Molecules can absorb infrared photons of specific wavelengths, highlighting the types and strengths of different chemical bonds present within the molecules.
Explanation:
Infrared spectroscopy evaluates the vibrational energy states found in molecules. When a molecule absorbs infrared photons, the chemical bonds vibrate at distinct frequencies. Scrutinizing the alterations in vibrational energy within a molecule allows for the identification of different bond types and consequently the molecule’s general structure. The vibrational behaviors of a molecule encompass bending, stretching, and scissoring motions.
