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Brut
2 months ago
13

1. Describe the methods by which an electric potential develops in primary cells and dry cells.

Physics
1 answer:
ValentinkaMS [3.4K]2 months ago
6 0

Response:

In primary cells, an electric potential arises due to chemical reactions occurring between the internal plates. Zinc ions, which are positively charged, move into the acid, while freed electrons from zinc atoms accumulate on the zinc plate, leading to a negative charge. Concurrently, positively charged hydrogen ions from the acid strip electrons from the copper plate, giving it a positive charge. Electrons transition from the zinc plate to the copper plate through a conductor for the duration of the chemical reaction.

Dry cells create electric potential similarly through internal chemical processes. Electrons taken from a carbon rod gather on a zinc can, resulting in a positive charge on the rod and a negative charge on the can; thus establishing an electric potential between them. As long as the conductive link remains intact, electrons transfer from the can to the rod.

Electric potential in generators is produced through magnetic induction. When a conductive rod is moved within the magnetic field of a horseshoe magnet, it generates an electric potential along the rod. Electrons travel through the rod from one end to the other for as long as the movement persists. The direction of movement is influenced by whether the rod is being moved against or with the magnetic field lines. Generators typically consist of several conductors fixed onto a rotating cylinder situated in a magnetic field.

Thermocouples convert heat to electric potential. A junction is created by connecting two metal strips at one end, while their other ends remain separated. Heating the junction raises the temperature of both strips. The ends that are not heated generate electric charges due to differing temperatures. Connecting these ends with a conductive wire allows electrons to flow through. The voltage generated increases with the temperature difference between the ends and the junction.

a. Increase

b. Decrease

c. Decrease

To convert watt-hours (Wh) to British thermal units (Btu), divide the Wh amount by 0.293, since 1 Btu = 0.293 Wh. Thus, 0.8 ÷ 0.293 = 2.73 Btu

Calculating energy usage: 365 days × 10 hours × 40 W = 146,000 Wh, equivalently 146 kWh

Clarification:

Penn Foster

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You apply the brakes of your car abruptly and your book starts sliding off the front seat. Three observers sitting in the car ex
Softa [3030]

Answer:

All observers are accurate.

Explanation:

This situation reflects a matter of reference frames regarding the book's motion as perceived by different observers.

From their distinct frames of reference, each observer's perspective is valid.

Observer A is in an inertial reference frame.

Observers capable of explaining the book's behavior and its relationship to the car through the interplay of forces and changes in velocity are classified as being in inertial reference frames.

Observer A's observations illustrate this, for she pointed out the relative motion between the book and the car, indicating her position in an inertial reference frame.

Likewise, observers in these inertial reference frames can elucidate object velocity changes based on the forces affecting them from other objects.

This is exemplified by observer B, who notes the car's force impacting the book's velocity.

Observer C occupies a non-inertial reference frame, as Newton's laws of motion do not apply. This scenario arises within non-inertial frames.

7 0
2 months ago
A charge of 4.9 x 10-11 C is to be stored on each plate of a parallel-plate capacitor having an area of 150 mm2 and a plate sepa
Keith_Richards [3271]

Answer:2.53*10^-10F

Explanation:

C=£o£r*A/d

Where £ represents the permittivity constant

£o= 8.85*10^-12f/m

£r=6.3

A=150mm^2=0.015m^2

d=3.3mm= 0.0033m

C=8.85*10^-12*6.3*0.015/0.0033

C=8.85*6.3*10^-12*0.015/0.0033

C=55.755*0.015^-12/0.003

C=8.36/3.3*10^-13+3

C=2.53*10^-10F

7 0
2 months ago
A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90 s. You may ignore air
Sav [3153]

Answer:

Height (h) = 17 m

Velocity (v) = 18.6 m/s

Explanation: This problem can be solved using kinematic motion equations.

Given Data

Initial velocity (u) = 0

Acceleration (a) = g

Time (t) = 1.9 seconds

First, we calculate the height.

s=ut+0.5at^2\\h=ut+0.5at^2\\h=0*1.9+0.5*9.81*1.9^2\\h=17.707 m

Then, we find the final velocity

v=u+at\\v=0+9.81*1.9\\v=18.639

The acceleration graph is a linear representation described by y=9.8, as it remains constant:

The velocity graph can be represented by y=9.8x (where y signifies velocity and x indicates time):

The displacement graph can be described as y=4.9x^2 (with x as time and y as displacement):

These graphs apply exclusively from x=0 to x=1.9, so disregard other sections of the graphs.

5 0
3 months ago
A 6V radio with a current of 2A is turned on for 5 minutes. Calculate the energy transferred in joules
ValentinkaMS [3465]

Answer:

R=V/I=6/2=3 ohm

time = 5 minutes = 5*60=300 seconds

I=2 A

Energy = I²Rt=(2)²*3*300=4*900=3600 J

7 0
3 months ago
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