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Zolol
3 months ago
14

A mechanical high-speed bat is flying along a path perpendicular to a wall. it emits a sound with a frequency f0 . the night is

clear and the air is still. let the speed of sound waves in the still air be vs . the bat hears a sound wave reflected from the wall with a frequency fnew . from this information one can determine the speed vbat at which the bat is flying. install a detector at the wall. 0 bat f v what is the detected frequency? 1. f1 = vs + vbat vs f0 2. f1 = vs vs − vbat f0 3. f1 = vs vs + vbat f0 4. f1 = vs + vbat vs − vbat f0 5. f1 = 2 vs vs − vbat f0 6. f1 = vs − vbat vs f0 7. f1 = vs − vbat vs + vbat f0 8. f1 = f0 9. f1 = 2 vs vs + vbat f0
Physics
1 answer:
inna [3.1K]3 months ago
4 0
1. f1 = Vs + Vbat Vs fO
2. f1 = Vs Vs - Vbat fO
3. f1 = Vs Vs + Vbat fO
4. f1 = Vs + Vbat Vs - Vbat fO
5. f1 = 2Vs Vs - Vbat fO
6. f1 = Vs - Vbat Vs fO
7. f1 = Vs - Vbat Vs + Vbat fO
8. f1 = fO
9. f1 = 2Vs Vs + Vbat fO

The frequency that is detected is
f= (V+Vr) × fO/ (V + Vs)
The speed of sound is V = Vs
The speed of the receiver is Vr = O
For the speed of the source
Vs = -Vbat, indicating that the bat approaches the wall
Therefore, the correct formula is
f1 = (Vs / (Vs -Vbat)) × fO.
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