Answer:
The distance covered by the minutes hand is 39.60 cm.
Explanation:
Note: A clock has a circular shape, where the minutes hand acts as the radius, and its motion creates an arc.
Length of an arc is calculated as ∅/360(2πr)
L = ∅/360(2πr).................... Equation 1π
Here, L represents the arc’s length, ∅ is the angle made by the arc, and r is the arc’s radius.
Given: ∅ = 252°, r = 9 cm, π = 3.143.
Upon substituting these values into equation 1,
L = 252/360(2×3.143×9)
L = 0.7×2×3.143×9
L = 39.60 cm.
Thus, the distance traversed by the minutes hand is 39.60 cm.
Q = mCΔT, in which Q = energy required, m = mass of the block, C = specific heat, ΔT = temperature change.
Utilizing the values provided;
Q = 12*913*(118-20) = 1073688 J = 1073.688 kJ.
The correct option is B.
Answer:
The density comes out to be 
Mg/µL
Explanation:
Given data:
The density of nuclear matter is approximately 
kg/m³
1 ml corresponds to 1 cm³
To determine:
The density of nuclear matter in Mg/µL
Solution:
We recognize that:
1 Mg equals 1000 kg
Thus, 1 m³ is equal to cm³
Moreover, 1 cm³ is equivalent to 1 mL
Thus, we can conclude that 1 mL is equal to 10³ µL
With this, we convert the density as follows:
Density = kg/m³
Density = kg/m³ × 
Mg/µL
Density = Mg/µL
I will assume the girl is on the right while the boy is on the left.
The net force represents the total of all forces acting on an object, factoring in negatives.
Let the force from the boy be denoted as b. We’ll apply the formula F = ma.
b + 3.5 = 0.2(2.5)
This reduces to a straightforward algebraic problem. By solving, we find that the boy is applying a force of -3N to the left.
Answer:
$ 18.75
Explanation:
Given:
Dave's car has a capacity of 12 gallons.
If the tank is at 3/8 full prior to filling:
The cost of gasoline per gallon is $2.50.
The volume Dave needs to fill:
=
=
of full tank
=
Dave must fill 7.5 gallons.
Total amount Dave will pay:
7.5 gallons x $2.50 =
$ 18.75
Thus, Dave will spend $ 18.75 to completely fill the tank.
