A container is filled with 4.0 g and 5.0 g 02. The mixture is ignited produced water how much water is produced

Answer:

B, D

Explanation:

We need to recognize that the ice will rise in temperature from -6.5 ºC to 0 ºC for it to change into water.

Let's define q₁ as the heat needed to warm the ice to 0ºC, and q₂ as the heat for the transition from solid to liquid.

The calculation for q₁ is as follows:

q₁ = s x m x ΔT, where s represents the specific heat of ice (2.09 J/gºC), m is the mass, and ΔT is the temperature difference.

For q₂, the enthalpy of fusion is computed as:

q₂ = C x ΔT

with C indicating the specific heat for the phase transition, denoted as AH in kJ/mol.

All necessary data for computing q₁, q₂, and the total heat change (q₁ + q₂) is provided.

q₁ = 25.0 g x (2.09 J/gºC) x (0 - (-6.5 ºC))

q₁ = 339.6 J = 0.339 kJ

q₂ = (25 g/18 g/mol) x 6.02 kJ/mol = 1.39 x 6.02 kJ = 8.36 kJ

Combining these values gives us qtotal = 0.339 kJ + 8.36 kJ = 8.70 kJ.

Now we can answer the question:

(a) False, AH refers to the heat capacity during melting.

(b) True, as we concluded earlier.

(c) False, there’s only one phase transition from solid (ice) to liquid.

(d) True based on our calculations above.

(e) False, according to our findings.

The question lacks completeness; the full question is:

Determine the theoretical yield:

When excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide, sodium nitrate and copper(II) sulfide precipitate. For this reaction, 469 grams of copper(II) nitrate was combined with 156 grams of sodium sulfide yielding 272 grams of sodium nitrate.

Answer:

The theoretical yield of sodium nitrate is 340 grams.

Explanation:

Calculating moles of copper(II) nitrate =

Moles of sodium sulfide =

Based on the reaction, 1 mole of copper(II) nitrate reacts with 1 mole of sodium sulfide.

Thus, 2 moles of sodium sulfide will react with:

of copper(II) nitrate

Since sodium sulfide is in limiting quantities, the amount of sodium nitrate produced will depend on the moles of sodium sulfide available.

According to the reaction, 1 mole of sodium sulfide generates 2 moles of sodium nitrate; thus, 2 moles of sodium sulfide will yield:

sodium nitrate

The total mass of 4 moles of sodium nitrate is:

85 g/mol × 4 mol = 340 g

The theoretical yield of sodium nitrate amounts to 340 g.

The theoretical yield of sodium nitrate is 340 grams.

In the container with a volume of 1 L, the total amount of gas is 0.0446 moles, whereas in a 3 L container, it is 0.1334 moles. Explanation: Since 1 mole of gas occupies 22.4 liters, to find the total gas quantity present in both the 1 L and 3 L containers, we divide the respective volumes by the reciprocal of 22.4 liters, leading to the determination of the moles of gas at each volume. Hence for 1 L, there are 0.0446 moles, and for 3 L, it is calculated to be 0.1334 moles. Thus, it can concluded that the number of moles increases with a rise in volume or expansion of gas.

Answer:

The proportion of the family's overall yearly electricity that is attributed to running both air conditioners over the summer months is = 19.4 %

Explanation:

Monthly average electricity usage = 900 kWh

The family utilizes two window air conditioners to cool their residence during summer for three months.

The electricity usage for a single window-unit air conditioner = 350 kWh

The total power utilized by both window-unit air conditioners = 350(2) = 700 kWh

The total power consumed by two air conditioners for the summer months = 700 (3) = 2100 kWh

The annual total power consumption = 900 (12) = 10800 kWh

The percentage of the family's total annual electricity for operating the air conditioners during summer = = 19.4 %