Greetings!
To tackle this question, we will apply the
Henderson-Hasselbach equation and solve for the molar ratio. It’s essential to obtain the pKa value for Acetic Acid, which is listed in reference tables as
4.76:
![pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )](https://tex.z-dn.net/?f=pH%3DpKa%20%2B%20log%20%28%20%5Cfrac%7B%5BCH_3COONa%5D%7D%7B%5BCH_3COOH%5D%7D%20%29%20)
![\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BCH_3COOH%5D%7D%7B%5BCH_3COONa%7D%3D%2010%5E%7B%28pH-pKa%29%5E%7B-1%7D%7D%3D10%5E%7B%284-4%2C76%29%5E%7B-1%7D%7D%3D5%2C75%20)
Thus, the mole ratio of CH₃COOH to CH₃COONa is
5.75Wishing you a wonderful day!
Answer:
The molar concentration of Fe³⁺ in the unknown solution is 8.01x10⁻⁵M.
Explanation:
When creating a calibration curve in spectrophotometric analysis, you apply Lambert-Beer’s law, which indicates that the absorbance of a compound is directly related to its concentration:
A = E*l*C
Where A stands for absorbance, E is the molar absorption coefficient, l is the path length, and C represents the molar concentration
Using the line equation, you find:
y = 4541.6X + 0.0461
Where Y is the absorbance and X refers to the concentration - we will presume the concentration is expressed in molarity-
Given that the absorbance of the unknown is 0.410:
0.410 = 4541.6X + 0.0461
X = 8.01x10⁻⁵M
The molar concentration of Fe³⁺ in the unknown solution is 8.01x10⁻⁵M.
Answer:
The mole fraction of nitrogen is 0.52
Explanation:
Provided information:
Temperature = 31.2 °C
Pressure = 870.2 mmHg
Volume = 15.1 L
Mass of the mixture = 24.1 g
Mole fraction of nitrogen =?
Process:
Converting pressure:
870.2 / 760 = 1.12 atm
Converting temperature:
31.2 + 273 = 304.2 K
Total moles calculation:
PV = nRT
n = PV/RT
n = 1.12 atm × 15.1 L / 0.0821 L.atm. mol⁻¹.K⁻¹ × 304.2 K
n = 16.9 L.atm. / 25 L.atm. mol⁻¹
n = 0.676 mol
Let x be the number of moles of nitrogen.
Thus, the moles of CO₂ = 0.676 - x
The mass of nitrogen = x mol × 28 g/mol, and for CO₂ the mass = 44 g/mol (0.676 - x)
We have 24.1 = 28x + (29.7 - 44x)
Rearranging gives: 24.1 - 29.7 = 28x - 44x
-5.6 = -16 x
Therefore, x = 0.35
Mole fraction of nitrogen:
Mole fraction of nitrogen = moles of nitrogen / total moles
Mole fraction of nitrogen = 0.35 mol / 0.676 mol
Mole fraction of nitrogen = 0.52
Answer: D) X-rays exhibit lower frequency than microwaves
Explanation:
A scientific statement is one that relies on evidence gathered from experiments and direct observation of the natural world. Such a statement can be corroborated through appropriate experimental methods.
The option D illustrates a scientific statement because it allows for the frequency of both microwaves and X-rays to be assessed and contrasted. This process entails experimental and observational techniques, which validates it as a scientific statement.
Response:
0.8853 mL
Clarification:
Initially, we convert 13 lb to kg, remembering that 1 lb = 0.454 kg:
- 13 lb *
= 5.902 kg
Next, we determine the required mg of acetaminophen to administer, applying the recommended dosage and infant's weight:
- 15 mg/kg * 5.902 kg = 88.53 mg
Finally, we compute the necessary mL of suspension, utilizing its concentration:
- 88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL
