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Lunna
9 days ago
7

cite specific situation that you experienced at home or in school where magnet used to seperate mixtures?​

Chemistry
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All faculty members are happy to see students help each other. Dumbledore is particularly pleased with Hermione. Though, it shou
VMariaS [2998]

Answer:

m_{Mg}=30.8mgMg

Explanation:

Greetings,

According to the provided chemical equation, the production of 31.2 mL of hydrogen allows one to calculate its moles using the ideal gas equation as detailed below:

n_{H_2}=\frac{PV}{RT}=\frac{754torr*\frac{1atm}{760torr}*0.0312L}{0.082 \frac{atm*L}{mol*K}*298.15K}=1.27x10^{-3}molH_2

Since the ratio of hydrogen to magnesium is 1:1, its milligrams are derived through the following proportional factor calculation:

m_{Mg}=1.27x10^{-3}molH_2*\frac{1molMg}{1molH_2}*\frac{24.305gMg}{1molMg}*\frac{1000mgMg}{1gMg}\\m_{Mg}=30.8mgMg

Regards.

3 0
2 months ago
A plot of velocity versus substrate concentration for a simple enzyme-catalyzed reaction produces a _____. This indicates that a
castortr0y [3046]

Answer:

B) Hyperbolic curve; substrate saturation

Explanation:

Enzymatic kinetics examines the rates of reactions catalyzed by enzymes. These studies offer insights into the mechanism of the catalytic reaction and enzyme specificity. Determining the reaction rate facilitated by an enzyme is generally straightforward, as purification or isolation of the enzyme is frequently unnecessary. Measurements are taken under optimal conditions for pH, temperature, and the presence of cofactors, utilizing saturating substrate concentrations. Under these circumstances, the observed reaction rate is the maximum velocity (Vmax). The rate can be measured by monitoring either product formation or substrate consumption.

Following the rate of product formation (or substrate consumption) over time yields the so-called reaction progress curve, or merely, reaction kinetics. This reacts as a hyperbolic curve

5 0
1 month ago
The speed of light in a vacuum is 2.998 × 10 8 8 m/s. How long does it take for light to circumnavigate the Earth, which has a c
castortr0y [3046]

Answer:- 0.134 seconds

Solution:- The speed is given as 2.988*10^8\frac{m}{s} and the circumference is 24900 miles which is same as the distance light have to covered. It asks to calculate the time required to cover this distance by the light.

Unit conversion is needed from miles to meters since the speed is given in meters per second.

1 mile = 1609.34 meters

Thus, 24900mile(\frac{1609.34meter}{mile})

= 40072566 meters

Now, speed=\frac{distance}{time}

Rearranged for time, that gives: time=\frac{distance}{speed}

Inserting the values:

time=\frac{40072566meter}{2.988*10^8\frac{meter}{second}}

= 0.134 seconds

Hence, light would take 0.134 seconds to traverse the indicated distance. The answer without the unit is 0.134.

8 0
2 months ago
13.3 g of benzene (C6H6) is dissolved in 282 g of carbon tetrachloride. What is the molal concentration of benzene in this solut
Tems11 [2777]

Answer:

0.605 molal

Explanation:

Molality indicates the solute amount in a specific solvent mass.

Let’s find the amount of benzene solute.

Mass of benzene = 13.3g

Molar mass of C6H6 = 12*6 +1*6 =72+7=78g/mol

Amount of benzene = mass/molar mass

                           =13.3/78

                          =0.1705mol

Molality = amount of solute/mass of solvent in kg

Mass of solvent = 282g = 0.282kg

Molality = 0.1705/0.282

    =0.605 molal

6 0
2 months ago
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