Response:
The man's speed is 0.144 m/s
Explanation:
This exemplifies conservation of momentum.
The momentum of the ball prior to being caught must equal the momentum of the man-ball system after catching the ball.
Mass of the ball = 0.65 kg
Mass of the man = 54 kg
Speed of the ball = 12.1 m/s
The momentum of the ball before impact can be calculated as mass multiplied by velocity
= 0.65 x 12.1 = 7.865 kg-m/s
After catching the ball, the momentum of the combined system is
(0.65 + 54)Vf = 54.65Vf
Where Vf denotes their final shared velocity.
Setting the initial momentum equal to the final momentum,
7.865 = 54.65Vf
Vf = 7.865/54.65 = 0.144 m/s
Answer:
Statements 4, 6 & 7 are incorrect.
Explanation:
In any elastic collision, the overall momentum vector sum of the system remains zero.
In this scenario, an elastic collision occurs between the ball and a stationary wall. The ball's velocity will consistently revert after the impact, leading to a change in direction of momentum.
The initial momentum of the ball is represented as:
where:
m = mass of the ball
v = initial velocity of the body
post-collision for the elastic interaction:
- Here, the momentum changes solely in direction, thus contradicting statement 7.
- During the impact, both the ball and the wall exert forces on each other that are equal and opposite. The wall remains motionless, while the ball is influenced by the wall's reaction force, performing work on it, which contradicts statement 4.
- Given that this collision is elastic, the ball's form and dimensions do not alter.
- The previous points clearly indicate that not all provided statements hold true, thus violating statement 6.
To tackle this issue, it's essential to understand the conversion of pounds to kilograms:
1 lb = 0.45 Kg
By applying a straightforward rule of three
1 lb ---> 0.45 Kg
125 lb ---> x
Solving for x yields:
x = ((125) / (1)) * (0.45) = 56.25 Kg.
Response
her mass in kilograms is 56.25 Kg.
The force exerted on the car during the stop measures 6975 N.
Explanation: Given that the mass (m) is 930 kg, speed (s) at 56 km/h converts to 15 m/s, and the stopping time (t) is 2 s, we compute the force using F = m * a. Here, acceleration (a) can be obtained through a = s/t. The total force calculation confirms that F = 930 kg * (15 m/s) / 2 s results in 6975 N.
Answer:
1. Reactions involving oxidation and reduction along with proton pumping
2. Reactions involving phosphorylation and proton pumping
Explanation:
During oxidative phosphorylation, there is a transfer of electrons from donors to acceptors, which constitutes a redox reaction.
These redox reactions liberate energy that is utilized to produce ATP. In eukaryotic cells, these reactions are performed by protein complexes found in the mitochondria, while in prokaryotic cells, the proteins are positioned in the intermembrane space of the cells. These interconnected protein complexes are referred to as electron transport chains.
